Math Problem Statement

Let A be a square matrix such that det(A) = 12. Let B be the matrix obtained from A by multiplying the first row of A by 1/2. What is the determinant of matrix B?

Solution

The problem asks for the determinant of matrix BB, which is derived from matrix AA by multiplying the first row of AA by 12\frac{1}{2}. We are also given that the determinant of AA, denoted as det(A)\text{det}(A), is 12.

Key concept:

When a row of a matrix is multiplied by a scalar, the determinant of the new matrix is multiplied by that scalar. Specifically, if a row of a matrix AA is multiplied by a scalar kk, then the determinant of the new matrix is: det(B)=kdet(A)\text{det}(B) = k \cdot \text{det}(A) Here, the first row of matrix AA is multiplied by 12\frac{1}{2}, so the determinant of BB is: det(B)=12det(A)\text{det}(B) = \frac{1}{2} \cdot \text{det}(A) Substituting the given value det(A)=12\text{det}(A) = 12: det(B)=1212=6\text{det}(B) = \frac{1}{2} \cdot 12 = 6

Thus, the determinant of matrix BB is 66.

Let me know if you need further details or clarifications!

Related questions:

  1. What happens to the determinant if the second row of a matrix is multiplied by 13\frac{1}{3}?
  2. How would the determinant change if all rows of a matrix are multiplied by a constant?
  3. If two rows of a matrix are swapped, how does that affect the determinant?
  4. Can you explain how row operations affect the determinant?
  5. What happens to the determinant of a matrix if one row is added to another row?

Tip:

Always remember that multiplying a row by a scalar multiplies the determinant by that scalar. This rule only applies to single rows, not the entire matrix.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Matrix Operations
Determinants

Formulas

det(B) = k * det(A) where k is a scalar multiplier
If a row of a matrix is multiplied by k, the determinant is multiplied by k

Theorems

Multiplication of a matrix row by a scalar affects the determinant by the same scalar

Suitable Grade Level

Undergraduate (Linear Algebra level)