Math Problem Statement

Find the derivative f^' for each function.  Simply your answer.

f(x)=x^(2⁄3)-x^(1⁄3)+4

f(x)=(3x-2x^2 )(5+4x)

f(x)=e^x  sin⁡x

f(x)=(3-2x-x^2)/(x^2-1)

f(x)=x cos⁡x+sin⁡x

f(x)=(2x+5)/√x

Solution

Let's find the derivative f(x)f'(x) for each of the given functions and simplify the answers.

1. f(x)=x23x13+4f(x) = x^{\frac{2}{3}} - x^{\frac{1}{3}} + 4

To differentiate this, apply the power rule:

f(x)=23x23113x131f'(x) = \frac{2}{3}x^{\frac{2}{3} - 1} - \frac{1}{3}x^{\frac{1}{3} - 1} f(x)=23x1313x23f'(x) = \frac{2}{3}x^{-\frac{1}{3}} - \frac{1}{3}x^{-\frac{2}{3}}

2. f(x)=(3x2x2)(5+4x)f(x) = (3x - 2x^2)(5 + 4x)

Use the product rule: (uv)=uv+uv(uv)' = u'v + uv'.

Let u=3x2x2u = 3x - 2x^2 and v=5+4xv = 5 + 4x.

Differentiate uu and vv:

u=34xu' = 3 - 4x v=4v' = 4

Now apply the product rule:

f(x)=(34x)(5+4x)+(3x2x2)(4)f'(x) = (3 - 4x)(5 + 4x) + (3x - 2x^2)(4) f(x)=(15+12x20x16x2)+(12x8x2)f'(x) = (15 + 12x - 20x - 16x^2) + (12x - 8x^2) f(x)=24x28x+15f'(x) = -24x^2 - 8x + 15

3. f(x)=exsinxf(x) = e^x \sin x

Use the product rule:

Let u=exu = e^x and v=sinxv = \sin x.

Differentiate uu and vv:

u=exu' = e^x v=cosxv' = \cos x

Apply the product rule:

f(x)=excosx+exsinxf'(x) = e^x \cos x + e^x \sin x f(x)=ex(cosx+sinx)f'(x) = e^x (\cos x + \sin x)

4. f(x)=32xx2x21f(x) = \frac{3 - 2x - x^2}{x^2 - 1}

Use the quotient rule: (uv)=uvuvv2\left(\frac{u}{v}\right)' = \frac{u'v - uv'}{v^2}.

Let u=32xx2u = 3 - 2x - x^2 and v=x21v = x^2 - 1.

Differentiate uu and vv:

u=22xu' = -2 - 2x v=2xv' = 2x

Now apply the quotient rule:

f(x)=(22x)(x21)(32xx2)(2x)(x21)2f'(x) = \frac{(-2 - 2x)(x^2 - 1) - (3 - 2x - x^2)(2x)}{(x^2 - 1)^2}

Simplify the expression:

f(x)=2x2+22x3+2x(6x4x22x3)(x21)2f'(x) = \frac{-2x^2 + 2 - 2x^3 + 2x - (6x - 4x^2 - 2x^3)}{(x^2 - 1)^2} f(x)=4x3+2x24x+2(x21)2f'(x) = \frac{-4x^3 + 2x^2 - 4x + 2}{(x^2 - 1)^2}

5. f(x)=xcosx+sinxf(x) = x \cos x + \sin x

Use the product rule for the first term:

Let u=xu = x and v=cosxv = \cos x.

Differentiate uu and vv:

u=1u' = 1 v=sinxv' = -\sin x

Now apply the product rule:

f(x)=1cosx+x(sinx)+cosxf'(x) = 1 \cdot \cos x + x(-\sin x) + \cos x f(x)=cosxxsinxf'(x) = \cos x - x \sin x

6. f(x)=2x+5xf(x) = \frac{2x + 5}{\sqrt{x}}

This is a quotient. Simplify f(x)f(x) first:

f(x)=(2x+5)x12f(x) = (2x + 5)x^{-\frac{1}{2}}

Now use the product rule:

Let u=2x+5u = 2x + 5 and v=x12v = x^{-\frac{1}{2}}.

Differentiate uu and vv:

u=2u' = 2 v=12x32v' = -\frac{1}{2}x^{-\frac{3}{2}}

Apply the product rule:

f(x)=2x12+(2x+5)(12x32)f'(x) = 2x^{-\frac{1}{2}} + (2x + 5)\left(-\frac{1}{2}x^{-\frac{3}{2}}\right) f(x)=2x2x+52x32f'(x) = \frac{2}{\sqrt{x}} - \frac{2x + 5}{2x^{\frac{3}{2}}}

Would you like further details on any of these solutions, or do you have any questions?


5 Related Questions:

  1. How does the power rule apply to fractional exponents?
  2. What is the importance of the product rule in differentiation?
  3. How do you simplify expressions after applying the quotient rule?
  4. How do you handle derivatives of trigonometric functions?
  5. What are the common mistakes to avoid in differentiation?

Tip: Always simplify the function before differentiating if possible—it often makes the process easier and the derivative simpler.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Power Rule
Product Rule
Quotient Rule
Exponential Functions
Trigonometric Functions

Formulas

Power Rule: d/dx [x^n] = n*x^(n-1)
Product Rule: (uv)' = u'v + uv'
Quotient Rule: (u/v)' = (u'v - uv') / v^2
Derivative of e^x: d/dx [e^x] = e^x
Derivative of sin x: d/dx [sin x] = cos x
Derivative of cos x: d/dx [cos x] = -sin x

Theorems

Rules of Differentiation
Fundamental Theorem of Calculus

Suitable Grade Level

Grades 11-12 (Advanced Calculus)