Math Problem Statement

Find f'(x) for f(x) = (x^6 + 4) / x^6 using both the quotient rule and simplifying first.

Solution

To solve the given problem, we are asked to find the derivative of f(x)=x6+4x6f(x) = \frac{x^6 + 4}{x^6} using two methods:

  1. Quotient Rule, and
  2. Simplifying first.

Method 1: Using the Quotient Rule

The quotient rule states:

ddx(u(x)v(x))=v(x)u(x)u(x)v(x)(v(x))2\frac{d}{dx} \left( \frac{u(x)}{v(x)} \right) = \frac{v(x) \cdot u'(x) - u(x) \cdot v'(x)}{(v(x))^2}

For f(x)=x6+4x6f(x) = \frac{x^6 + 4}{x^6}:

  • u(x)=x6+4u(x) = x^6 + 4
  • v(x)=x6v(x) = x^6

Now we compute the derivatives:

  • u(x)=6x5u'(x) = 6x^5 (since the derivative of x6x^6 is 6x56x^5, and the derivative of a constant is 0)
  • v(x)=6x5v'(x) = 6x^5

Now apply the quotient rule:

f(x)=x66x5(x6+4)6x5(x6)2f'(x) = \frac{x^6 \cdot 6x^5 - (x^6 + 4) \cdot 6x^5}{(x^6)^2}

Simplify the numerator:

f(x)=6x116x5(x6+4)x12=6x116x1124x5x12f'(x) = \frac{6x^{11} - 6x^5(x^6 + 4)}{x^{12}} = \frac{6x^{11} - 6x^{11} - 24x^5}{x^{12}}

This simplifies to:

f(x)=24x5x12=24x7f'(x) = \frac{-24x^5}{x^{12}} = -\frac{24}{x^7}

So, the derivative using the quotient rule is:

f(x)=24x7f'(x) = -\frac{24}{x^7}

The correct answer from the multiple choices provided would be option B, as it matches the quotient rule expression before simplifying.

Method 2: Simplifying First

We can rewrite f(x)=x6+4x6f(x) = \frac{x^6 + 4}{x^6} by splitting it into two terms:

f(x)=x6x6+4x6=1+4x6f(x) = \frac{x^6}{x^6} + \frac{4}{x^6} = 1 + 4x^{-6}

Now, differentiate term by term:

  • The derivative of 11 is 0.
  • The derivative of 4x64x^{-6} is 24x7-24x^{-7}.

Thus:

f(x)=24x7f'(x) = -\frac{24}{x^7}

So, both methods give the same result:

f(x)=24x7f'(x) = -\frac{24}{x^7}

Summary:

  • Using the quotient rule, we find that f(x)=24x7f'(x) = -\frac{24}{x^7}.
  • Simplifying first gives the same result: f(x)=24x7f'(x) = -\frac{24}{x^7}.
  • The correct answer in the multiple-choice section is option B.

Would you like further details or clarifications on any steps?


Here are 5 related questions:

  1. How do you apply the product rule for differentiation?
  2. What is the chain rule in calculus, and when do you use it?
  3. How can you differentiate a function with multiple variables?
  4. What happens when you apply implicit differentiation to an equation?
  5. How would you integrate a function like x7x^{-7}?

Tip: Always try simplifying expressions before applying differentiation rules like the quotient rule to make calculations easier!

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Math Problem Analysis

Mathematical Concepts

Differentiation
Quotient Rule
Simplification

Formulas

Quotient Rule: (u/v)' = (v * u' - u * v') / v^2
Derivative of power functions: d/dx(x^n) = n * x^(n-1)

Theorems

Quotient Rule
Basic Derivative Rules

Suitable Grade Level

Grades 11-12 (or introductory calculus)