Math Problem Statement
Solution
Let’s examine each part of the question one by one based on the provided graph of , the derivative of .
(a) On what intervals is increasing? Decreasing?
For to be increasing, must be positive (above the x-axis). Similarly, is decreasing where is negative (below the x-axis).
From the graph:
- is increasing on the interval where .
- is decreasing on the interval where .
(b) Locate the -value(s) where has a local maximum and minimum.
Local maxima and minima of occur where (crosses the x-axis) and changes sign:
- At : changes from negative to positive, indicating a local minimum of .
- At : changes from positive to negative, indicating a local maximum of .
- At : changes from negative to positive, indicating another local minimum of .
Thus:
- Local maximum at
- Local minima at and
(c) On what intervals is concave upward? Concave downward?
Concavity of depends on the derivative :
- is concave upward where is increasing (positive slope).
- is concave downward where is decreasing (negative slope).
From the graph:
- is concave upward on the intervals where has a positive slope.
- is concave downward on the interval where has a negative slope.
(d) Locate the -value(s) where has an inflection point.
Inflection points occur where the concavity changes, which is where the slope of changes from positive to negative or vice versa.
From the graph:
- The concavity changes at and .
Thus, the inflection points of are at and .
Would you like further clarification on any part? Here are some related questions that expand on these concepts:
- What does the graph of look like based on the information given about ?
- How would changes in 's behavior affect the second derivative and, consequently, the concavity of ?
- Can we determine the relative sizes of the maximum and minimum values of at the identified points?
- How would the intervals where is increasing or decreasing change if was shifted vertically?
- What impact would adding a constant to have on the locations of maxima, minima, and inflection points?
Tip: Remember that inflection points in a function occur where the second derivative changes sign, corresponding to changes in the slope of in this context.
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Math Problem Analysis
Mathematical Concepts
Calculus
Derivatives
Concavity
Inflection Points
Increasing and Decreasing Intervals
Formulas
If f'(x) > 0, f(x) is increasing
If f'(x) < 0, f(x) is decreasing
Concavity determined by f'(x) slope
Inflection points where concavity changes
Theorems
First Derivative Test
Second Derivative Test
Suitable Grade Level
Grades 11-12 or early college calculus
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