Math Problem Statement

find the derivative of the function f(x) = (3x^2 - 2x + 5)^10

Solution

To find the derivative of the function f(x)=(3x22x+5)10f(x) = (3x^2 - 2x + 5)^{10}, we will apply the chain rule.

The chain rule states that if you have a composite function f(g(x))f(g(x)), then its derivative is:

f(x)=f(g(x))g(x)f'(x) = f'(g(x)) \cdot g'(x)

Here, f(x)=(u(x))10f(x) = (u(x))^{10}, where u(x)=3x22x+5u(x) = 3x^2 - 2x + 5.

Step 1: Differentiate the outer function

The derivative of (u(x))10(u(x))^{10} with respect to u(x)u(x) is:

ddu[u(x)10]=10(u(x))9=10(3x22x+5)9\frac{d}{du} \left[ u(x)^{10} \right] = 10 \cdot (u(x))^9 = 10 \cdot (3x^2 - 2x + 5)^9

Step 2: Differentiate the inner function

Now, find the derivative of u(x)=3x22x+5u(x) = 3x^2 - 2x + 5:

u(x)=ddx[3x22x+5]=6x2u'(x) = \frac{d}{dx} \left[ 3x^2 - 2x + 5 \right] = 6x - 2

Step 3: Apply the chain rule

Now multiply the derivative of the outer function by the derivative of the inner function:

f(x)=10(3x22x+5)9(6x2)f'(x) = 10 \cdot (3x^2 - 2x + 5)^9 \cdot (6x - 2)

Thus, the derivative of the function is:

f(x)=10(3x22x+5)9(6x2)f'(x) = 10(3x^2 - 2x + 5)^9(6x - 2)

Would you like more details or have any questions?

Here are 5 related questions for further practice:

  1. What is the second derivative of f(x)=(3x22x+5)10f(x) = (3x^2 - 2x + 5)^{10}?
  2. How would you find the derivative of f(x)=(2x3x+4)7f(x) = (2x^3 - x + 4)^7?
  3. What is the derivative of f(x)=(x2+1)5f(x) = (x^2 + 1)^5?
  4. Can you find the derivative of f(x)=sin4(x23x)f(x) = \sin^4(x^2 - 3x)?
  5. How do you apply the chain rule to f(x)=ln(5x23x+2)f(x) = \ln(5x^2 - 3x + 2)?

Tip: Always check if the chain rule applies when differentiating composite functions!

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Math Problem Analysis

Mathematical Concepts

Calculus
Derivatives
Chain Rule
Polynomial Functions

Formulas

Chain rule: f'(x) = f'(g(x)) * g'(x)
Power rule: d/dx[u^n] = n * u^(n-1) * du/dx

Theorems

Chain Rule

Suitable Grade Level

Grades 11-12 or early college level