what is the density of a piece of gold (each edge is 1.5 cm) with a mass of 65.1g

To find the density of a piece of gold, we need to use the formula for density:

\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]

### Step 1: Calculate the Volume of the Gold

The gold piece is a cube with each edge measuring 1.5 cm. The volume \( V \) of a cube can be calculated using the formula:

\[
V = \text{side}^3
\]

Substitute the side length:

\[
V = (1.5 \, \text{cm})^3 = 1.5 \times 1.5 \times 1.5 = 3.375 \, \text{cm}^3
\]

### Step 2: Calculate the Density

Now, use the mass of the gold piece (65.1 g) to find the density:

\[
\text{Density} = \frac{65.1 \, \text{g}}{3.375 \, \text{cm}^3}
\]

Let's compute the density.

\[
\text{Density} \approx 19.29 \, \text{g/cm}^3
\]

### Conclusion

The density of the piece of gold is approximately **19.29 g/cm³**.

Would you like more details on this solution, or do you have any questions?

### Related Questions

1. What is the density of a different material if the mass and volume are given?
2. How would the density change if the dimensions of the cube are doubled?
3. How can density be used to identify an unknown material?
4. What are the units of density in the International System of Units (SI)?
5. How does temperature affect the density of materials?

#### Tip: Remember that density is a characteristic property of a material and does not depend on the size or shape of the sample.

Find the density of a gold cube with an edge of 1.5 cm and a mass of 65.1 g. This problem involves calculating the volume of a cube and using the density formula. Suitable for students in Grades 6-8.

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