Math Problem Statement

what is the density of a piece of gold (each edge is 1.5 cm) with a mass of 65.1g

Solution

To find the density of a piece of gold, we need to use the formula for density:

Density=MassVolume\text{Density} = \frac{\text{Mass}}{\text{Volume}}

Step 1: Calculate the Volume of the Gold

The gold piece is a cube with each edge measuring 1.5 cm. The volume VV of a cube can be calculated using the formula:

V=side3V = \text{side}^3

Substitute the side length:

V=(1.5cm)3=1.5×1.5×1.5=3.375cm3V = (1.5 \, \text{cm})^3 = 1.5 \times 1.5 \times 1.5 = 3.375 \, \text{cm}^3

Step 2: Calculate the Density

Now, use the mass of the gold piece (65.1 g) to find the density:

Density=65.1g3.375cm3\text{Density} = \frac{65.1 \, \text{g}}{3.375 \, \text{cm}^3}

Let's compute the density.

Density19.29g/cm3\text{Density} \approx 19.29 \, \text{g/cm}^3

Conclusion

The density of the piece of gold is approximately 19.29 g/cm³.

Would you like more details on this solution, or do you have any questions?

Related Questions

  1. What is the density of a different material if the mass and volume are given?
  2. How would the density change if the dimensions of the cube are doubled?
  3. How can density be used to identify an unknown material?
  4. What are the units of density in the International System of Units (SI)?
  5. How does temperature affect the density of materials?

Tip: Remember that density is a characteristic property of a material and does not depend on the size or shape of the sample.

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Math Problem Analysis

Mathematical Concepts

Geometry
Measurement
Density Calculation

Formulas

Density = Mass / Volume
Volume of a cube = side^3

Theorems

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Suitable Grade Level

Grades 6-8