https://file.aiquickdraw.com/mathbot/file/1726285714326jaxbyv82.jpg

To solve the question regarding the density of the object, we can use the formula for density:

\[
\text{Density} = \frac{\text{Mass}}{\text{Volume displaced}}
\]

From the image, we know:
- The mass of the object is **100 g**.
- The water level initially is at **50 cm³**.
- After the object is immersed, the water level rises to **90 cm³**.

So, the volume displaced by the object is:

\[
\text{Volume displaced} = 90 \, \text{cm}^3 - 50 \, \text{cm}^3 = 40 \, \text{cm}^3
\]

Now, applying the density formula:

\[
\text{Density} = \frac{100 \, \text{g}}{40 \, \text{cm}^3} = 2.5 \, \text{g/cm}^3
\]

Thus, the correct answer is **2.5 g/cm³**, as indicated.

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Would you like a further breakdown of this solution or details on a related concept?

Here are 5 related questions you might find interesting:
1. How would the density change if the mass were halved but the volume stayed the same?
2. How does the concept of buoyancy relate to the object's density compared to water?
3. Can an object with the same volume but a higher mass have a lower density?
4. What happens to the water level if an object less dense than water is placed in it?
5. How is the Archimedes' principle applied in this scenario?

**Tip**: To confirm whether an object will float or sink in water, compare its density to that of water (1 g/cm³). If it's less than 1, the object will float; otherwise, it will sink.

An object of mass 100 g is immersed in water as shown in the diagram. What is the density of the material from which the object is made?

Solve for the density of an object with a mass of 100 g using volume displacement in water. The object displaces 40 cm³ of water, resulting in a density of 2.5 g/cm³. Explore the application of the density formula and the concept of volume displacement in this solution. Suitable for students in Grades 7-9.

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