To solve the problem, we need to calculate the density of the object using the following formula for density ($d$):

$d = \frac{\text{mass of the object}}{\text{volume of the object}}$

From the image, we have:

• Mass of the object = 43.343 g
• Volume of water in the cylinder before the object is submerged = 28.21 mL
• Volume of water + object in the cylinder = 35.77 mL

The volume of the object can be found by subtracting the initial volume of water from the volume of water after the object is submerged:

$\text{Volume of the object} = 35.77 \, \text{mL} - 28.21 \, \text{mL} = 7.56 \, \text{mL}$

Now, we can calculate the density:

$d = \frac{43.343 \, \text{g}}{7.56 \, \text{mL}} = 5.73 \, \text{g/mL}$

So, the density of the object is approximately 5.73 g/mL.

Would you like further details on how to handle similar problems or go deeper into density concepts?

Here are 5 related questions to expand your understanding:

1. How does the displacement method work in measuring the volume of irregular objects?
2. Why does density have units of g/mL or g/cm³, and how are they related?
3. How would the density change if the object's mass were doubled but its volume remained the same?
4. Can you apply this density calculation method for objects that float in water? Why or why not?
5. How does temperature affect the density of materials?

Tip: Always ensure the volume measurements are precise when calculating density, as small errors in volume can lead to significant deviations in the final result.