Math Problem Statement

Compute the definite integral: ∫₀^∞ (x² / ((x² + 4)(x² + 9))) dx

Solution

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Problem:

You are asked to compute the definite integral:

0(x2(x2+4)(x2+9))dx\int_{0}^{\infty} \left( \frac{x^2}{(x^2 + 4)(x^2 + 9)} \right) \, dx

Solution:

This type of integral is commonly solved using the method of partial fractions.

  1. Decompose the integrand into partial fractions:

    The integrand can be decomposed as:

    x2(x2+4)(x2+9)=Ax2+4+Bx2+9\frac{x^2}{(x^2 + 4)(x^2 + 9)} = \frac{A}{x^2 + 4} + \frac{B}{x^2 + 9}

    To find AA and BB, multiply both sides by (x2+4)(x2+9)(x^2 + 4)(x^2 + 9) and equate coefficients:

    x2=A(x2+9)+B(x2+4)x^2 = A(x^2 + 9) + B(x^2 + 4)

    Expanding and combining like terms:

    x2=(A+B)x2+(9A+4B)x^2 = (A + B)x^2 + (9A + 4B)

    Comparing coefficients of x2x^2 and the constant term on both sides:

    • Coefficient of x2x^2: 1=A+B1 = A + B
    • Constant term: 0=9A+4B0 = 9A + 4B
  2. Solve the system of equations:

    From 1=A+B1 = A + B and 0=9A+4B0 = 9A + 4B, solve for AA and BB:

    • From 1=A+B1 = A + B, we have B=1AB = 1 - A.

    • Substitute B=1AB = 1 - A into 0=9A+4B0 = 9A + 4B:

      0=9A+4(1A)0=9A+44A5A=4A=450 = 9A + 4(1 - A) \Rightarrow 0 = 9A + 4 - 4A \Rightarrow 5A = -4 \Rightarrow A = -\frac{4}{5}

    • Substituting A=45A = -\frac{4}{5} into B=1AB = 1 - A:

      B=1+45=95B = 1 + \frac{4}{5} = \frac{9}{5}

    So the decomposition is:

    x2(x2+4)(x2+9)=45x2+4+95x2+9\frac{x^2}{(x^2 + 4)(x^2 + 9)} = \frac{-\frac{4}{5}}{x^2 + 4} + \frac{\frac{9}{5}}{x^2 + 9}

  3. Integrate term by term:

    Now, integrate each term separately:

    0(4/5x2+4+9/5x2+9)dx\int_{0}^{\infty} \left( -\frac{4/5}{x^2 + 4} + \frac{9/5}{x^2 + 9} \right) dx

    These integrals are standard:

    dxx2+a2=1atan1(xa)+C\int \frac{dx}{x^2 + a^2} = \frac{1}{a} \tan^{-1} \left( \frac{x}{a} \right) + C

    So,

    045x2+4dx=4512[π2]=2π5\int_{0}^{\infty} \frac{-\frac{4}{5}}{x^2 + 4} dx = -\frac{4}{5} \cdot \frac{1}{2} \left[ \frac{\pi}{2} \right] = -\frac{2\pi}{5}

    and

    095x2+9dx=9513[π2]=3π5\int_{0}^{\infty} \frac{\frac{9}{5}}{x^2 + 9} dx = \frac{9}{5} \cdot \frac{1}{3} \left[ \frac{\pi}{2} \right] = \frac{3\pi}{5}

  4. Final Answer:

    The value of the integral is:

    3π52π5=π5\frac{3\pi}{5} - \frac{2\pi}{5} = \frac{\pi}{5}

So, the value of the integral is:

π5\boxed{\frac{\pi}{5}}

Would you like further details or explanations on any part of this solution?

Follow-Up Questions:

  1. How is partial fraction decomposition used to simplify integrals?
  2. What is the importance of recognizing standard integral forms?
  3. Can this integral be solved using any other methods, such as contour integration?
  4. How would the integral change if the limits were different, say from 00 to 11?
  5. What are some practical applications of integrals like this in physics or engineering?

Tip:

When solving definite integrals involving rational functions, always check if the integrand can be simplified using partial fraction decomposition. This technique often turns a complex integral into a sum of simpler ones.

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Math Problem Analysis

Mathematical Concepts

Calculus
Integral Calculus
Partial Fractions

Formulas

Partial Fraction Decomposition: x² / ((x² + 4)(x² + 9)) = A / (x² + 4) + B / (x² + 9)
Standard Integral: ∫ dx / (x² + a²) = (1/a) arctan(x/a) + C

Theorems

Fundamental Theorem of Calculus

Suitable Grade Level

Undergraduate Calculus