Math Problem Statement

Q 9 - On eighth Feb, 2005 it was Tuesday. What was the week's day on eighth Feb, 2004?

Solution

To solve this problem, we need to determine the day of the week on February 8, 2004, given that February 8, 2005, was a Tuesday.

Step 1: Identify if 2004 is a leap year

  • A year is a leap year if it is divisible by 4. However, if it is divisible by 100, it must also be divisible by 400.
  • 2004 is divisible by 4, and since it's not divisible by 100, it is a leap year. Therefore, 2004 has 366 days.

Step 2: Calculate the day difference between Feb 8, 2005, and Feb 8, 2004

  • Since 2004 is a leap year, the number of days from February 8, 2004, to February 8, 2005, is 366 days.

Step 3: Calculate the day of the week for Feb 8, 2004

  • Since 366 days are equivalent to 52 weeks and 2 days (because 366÷7=52366 \div 7 = 52 weeks and 22 days).
  • Therefore, February 8, 2004, was 2 days before February 8, 2005.

If February 8, 2005, was a Tuesday, then:

  • One day before Tuesday is Monday.
  • Two days before Tuesday is Sunday.

Conclusion:

The day of the week on February 8, 2004, was Sunday.


Would you like more details or have any questions about this calculation? Here are 5 related questions to explore further:

  1. How do you calculate the day of the week for any given date?
  2. What is the difference between a leap year and a regular year?
  3. How do leap years affect calendar calculations?
  4. How can modular arithmetic be used to solve day-of-the-week problems?
  5. How can you determine the day of the week for historical events?

Tip: When solving date-related problems, always remember to account for leap years, as they can shift days of the week by an extra day.

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Math Problem Analysis

Mathematical Concepts

Calendar Calculations
Leap Years

Formulas

Days of the Week Calculation
Leap Year Determination

Theorems

Leap Year Rule
Modulo Arithmetic

Suitable Grade Level

Grades 6-8