Math Problem Statement

The image shows a cuboid with dimensions 8 cm, 6 cm, and 12 cm, asking for: a. Perpendicular diagonal between points. b. Longest diagonal of the cuboid. c. Surface area. d. Volume.

Solution

The image shows a cuboid with the dimensions 8cm8 \, \text{cm}, 6cm6 \, \text{cm}, and 12cm12 \, \text{cm}, and several questions that are listed next to it. The questions ask to calculate:

a. Perpendicular diagonal between points.

b. Longest diagonal of the cuboid.

c. Surface area.

d. Volume.

Let me go ahead and solve these problems.

a. Perpendicular Diagonal (Diagonal of a Face)

Assume the question asks for the diagonal across a face of the cuboid, such as the diagonal between the sides 6 cm and 8 cm. The diagonal of a rectangle can be calculated using the Pythagorean theorem: d=l2+w2d = \sqrt{l^2 + w^2} Where l=8cml = 8 \, \text{cm} and w=6cmw = 6 \, \text{cm}.

b. Longest Diagonal (Body Diagonal)

For the longest diagonal, which is the body diagonal of the cuboid, we use the 3D Pythagorean theorem: d=l2+w2+h2d = \sqrt{l^2 + w^2 + h^2} Where l=12cml = 12 \, \text{cm}, w=8cmw = 8 \, \text{cm}, and h=6cmh = 6 \, \text{cm}.

c. Surface Area

The surface area of the cuboid is the sum of the areas of all six faces: A=2(lw+lh+wh)A = 2(lw + lh + wh) Where l=12cml = 12 \, \text{cm}, w=8cmw = 8 \, \text{cm},

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Math Problem Analysis

Mathematical Concepts

Geometry
3D Shapes
Pythagorean Theorem

Formulas

Face diagonal: d = sqrt(l^2 + w^2)
Body diagonal: d = sqrt(l^2 + w^2 + h^2)
Surface area: A = 2(lw + lh + wh)
Volume: V = l * w * h

Theorems

Pythagorean theorem

Suitable Grade Level

Grades 7-9