Math Problem Statement
Solution
The problem you're dealing with involves a cube whose edges are expanding at a rate of 6 centimeters per second. We are asked to determine how fast the volume of the cube is changing when each edge is 2 centimeters and 10 centimeters.
Step-by-Step Solution:
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Volume of a Cube Formula:
The volume of a cube is given by: where is the length of an edge of the cube. -
Given Rate of Change:
The rate at which the edge length changes is given as: where is the length of the edge and is the rate of change of the edge length. -
Differentiate the Volume Formula:
To find how fast the volume is changing, we differentiate the volume equation with respect to time : where is the rate of change of the volume. -
Substitute Known Values:
Now, we can substitute the given values into the differentiated equation.-
(a) When cm:
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(b) When cm:
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Final Answers:
- (a) When the edge is 2 cm, the volume is changing at 72 cubic centimeters per second.
- (b) When the edge is 10 cm, the volume is changing at 1800 cubic centimeters per second.
Would you like any further clarifications or additional questions related to this? Here's a list of related questions you might find interesting:
- How does the rate of change of volume vary with different edge lengths?
- Can you calculate the rate of change in surface area given the same edge length expansion rate?
- What is the physical significance of the differentiation in this type of problem?
- How does the volume of a cube relate to its surface area mathematically?
- What happens to the rate of change if the edge length rate of change is halved?
Tip: When dealing with related rates, always express the variables in terms of each other, and then differentiate with respect to time, keeping track of the rates you're given.
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Math Problem Analysis
Mathematical Concepts
Calculus
Related Rates
Volume of a Cube
Formulas
V = s^3
dV/dt = 3s^2 * ds/dt
Theorems
Related Rates Theorem
Suitable Grade Level
Grades 11-12
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