Math Problem Statement
830, 835, 890, 810, 835, 836, 869, 845, 898, 890,820, 860, 832, 833, 855, 845, 804, 808, 812, 840, 885, 835, 835, 836, 878, 840, 868, 890, 806, 840. Draw a frequency distribution table for the given data.
Solution
To create a frequency distribution table, we first need to organize the data into classes (intervals) and then count the frequency of values falling into each class. Here’s how to do it:
Step 1: Find the Range
The range is the difference between the maximum and minimum values in the data set.
- Maximum value: 898
- Minimum value: 804
Range:
Step 2: Determine the Number of Classes
The number of classes can be determined by using Sturges' formula:
where is the number of data points.
Here, .
So, let's use 6 classes.
Step 3: Determine the Class Width
The class width is calculated by dividing the range by the number of classes:
Step 4: Create the Class Intervals
We start with the minimum value and create class intervals with the class width.
Step 5: Tally the Frequencies
Now we tally the frequency of data points in each class interval.
Class Interval | Frequency |
---|---|
804 - 819 | 6 |
820 - 835 | 9 |
836 - 851 | 7 |
852 - 867 | 3 |
868 - 883 | 3 |
884 - 899 | 2 |
This is your frequency distribution table.
Do you want more details or have any questions?
Related Questions:
- How do we calculate the mean from the frequency distribution table?
- How does changing the number of classes affect the frequency distribution?
- What is a histogram, and how can it be used to visualize this data?
- How would the frequency distribution table look if we used 7 classes instead of 6?
- Can we use different class intervals, and how does it affect the results?
Tip: When choosing the number of classes in a frequency distribution, it’s often helpful to experiment with different intervals to see which gives the most meaningful insights.
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Math Problem Analysis
Mathematical Concepts
Statistics
Frequency Distribution
Formulas
Sturges' formula
Theorems
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Suitable Grade Level
Advanced High School
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