Math Problem Statement
Six married couple and 4 men are sitting in a room. Find the number of ways in which 4 people can be selected so that no couples are in the committe together.
Solution
Let's solve this problem step by step.
Problem Restatement:
We have six married couples and four additional men, making a total of people. We need to select 4 people such that no couple is selected together.
Step 1: Counting Total Possible Selections
The total number of ways to select 4 people from 16 (without any restrictions) is given by the combination formula:
Step 2: Counting Selections that Include Couples
Next, we must subtract the cases where at least one couple is selected together.
Case 1: One couple and two other people
- Choose 1 couple from the 6 married couples: ways.
- Choose 2 more people from the remaining 14 (excluding the couple selected): ways.
So, the number of ways to select 4 people where exactly one couple is selected is:
Case 2: Two couples
- Choose 2 couples from the 6 married couples: ways.
- No additional people need to be selected because 4 people have already been chosen.
So, the number of ways to select 4 people with exactly two couples is:
Step 3: Subtracting Unwanted Cases
The number of valid selections is:
Step 4: Calculation
- Calculate :
- Calculate :
- Calculate :
- Add the cases for two couples:
- Subtract this from the total:
Final Answer:
The number of ways to select 4 people such that no couple is selected together is .
Would you like any further details or have any questions?
Here are five questions that relate to this problem:
- How would the solution change if there were 5 couples and 6 additional people?
- What if we had to select 5 people instead of 4, still ensuring no couples are selected together?
- How does the problem change if the additional men are replaced with additional women?
- What is the general formula for selecting people from such that no couple is together?
- How would the approach change if we were allowed to select exactly one couple but not two?
Tip: When solving combinatorial problems, always consider breaking down the problem into smaller cases to avoid overcounting or undercounting.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Combinatorics
Combinations
Counting principles
Formulas
Combination formula \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \)
Theorems
-
Suitable Grade Level
Advanced High School
Related Recommendation
Combinatorics Problem: Selecting Friends with One Married Couple
Ways Four Couples Can Arrange Themselves in a Row
Combinatorics Problem: Guessing Married Couples at a Party
Calculate Different Pairs of Dancers from 6 Males and 4 Females
Wedding Photography: Arranging 6 People with Restrictions on Bride and Groom