Math Problem Statement
On the sides of a triangle ABC several points are taken so that none of them coincides with the vertices of the triangle. Any three of these points not lying on one line are vertices of some triangle. How many such triangles are there, with one vertex on AB and one vertex on BC, if there are six possible points on the side AB, seven possible points on the side BC, and eight possible points on the side AC?
Solution
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Math Problem Analysis
Mathematical Concepts
Combinatorics
Geometric Shapes
Triangle Formation
Formulas
Total triangles = (Points on AB) × (Points on BC) × (Points on AC)
Theorems
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Suitable Grade Level
Grades 9-12
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