https://file.aiquickdraw.com/mathbot/file/17293978425847kg087le.jpg

In the image, we see a geometric figure composed of five identical equilateral triangles arranged in a row. The problem asks for the number of rhombuses that can be formed within this configuration.

A rhombus is a quadrilateral where all sides have equal length, and in this case, the rhombuses can be formed by combining pairs of adjacent triangles.

- For each two adjacent triangles, we can find one rhombus. In total, there are 4 pairs of adjacent triangles.
- Additionally, we can also count larger rhombuses that span more than two triangles.

Let's count carefully:
1. There are 4 smaller rhombuses formed by combining each pair of adjacent triangles.
2. There's an additional large rhombus that spans the entire set of 4 triangles in the middle.

Thus, the total number of rhombuses in the figure is **5**.

Would you like further clarification or details? Here are five related questions that can extend this topic:

1. How can we generalize this method to a row of *n* equilateral triangles?
2. What is the difference between rhombuses and parallelograms in this context?
3. Can we form other types of quadrilaterals in the figure? How many?
4. How does the orientation of triangles affect the number of rhombuses?
5. How would the count change if the figure was made of squares instead of triangles?

**Tip:** When counting geometric shapes, carefully look for both small and larger combinations to ensure all possibilities are included.

The figure below is formed by 5 identical equilateral triangles. We can find ____ rhombuses in the figure.

Explore how to count the rhombuses formed by a figure composed of 5 identical equilateral triangles. This geometry problem challenges students to recognize patterns and shapes within a geometric configuration. Suitable for students in Grades 6-8.

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