How many number of at least three different digit numbers can be formed from the integers 1,2,3,4,5,6?

To determine the number of numbers with at least three different digits that can be formed from the integers 1, 2, 3, 4, 5, and 6, we need to consider combinations of digits and permutations of those combinations.

### Step-by-Step Solution

1. **Identify Total Digits and Constraints:**
   - We have 6 digits: {1, 2, 3, 4, 5, 6}.
   - The number must have at least three different digits.
   - Digits can be repeated in different positions, but the digits themselves must be unique within each number.

2. **Calculate the Number of Valid Numbers:**
   - Calculate for 3-digit, 4-digit, 5-digit, and 6-digit numbers separately and then sum the results.

#### Number of 3-digit numbers:
   - Choose 3 digits from 6: \( \binom{6}{3} \)
   - Permute those 3 digits: \( 3! \)

\[ \binom{6}{3} \times 3! = 20 \times 6 = 120 \]

#### Number of 4-digit numbers:
   - Choose 4 digits from 6: \( \binom{6}{4} \)
   - Permute those 4 digits: \( 4! \)

\[ \binom{6}{4} \times 4! = 15 \times 24 = 360 \]

#### Number of 5-digit numbers:
   - Choose 5 digits from 6: \( \binom{6}{5} \)
   - Permute those 5 digits: \( 5! \)

\[ \binom{6}{5} \times 5! = 6 \times 120 = 720 \]

#### Number of 6-digit numbers:
   - Choose 6 digits from 6: \( \binom{6}{6} \)
   - Permute those 6 digits: \( 6! \)

\[ \binom{6}{6} \times 6! = 1 \times 720 = 720 \]

### Total Sum:
\[ 120 (3 \text{-digit}) + 360 (4 \text{-digit}) + 720 (5 \text{-digit}) + 720 (6 \text{-digit}) = 1920 \]

### Conclusion
The total number of numbers with at least three different digits that can be formed from the integers 1, 2, 3, 4, 5, and 6 is \( \boxed{1920} \).

Would you like further details or have any questions?

Here are five related questions you might find interesting:
1. How many 4-digit numbers can be formed from the digits 0, 1, 2, 3, 4, 5?
2. How many different ways can 5 people be seated in a row?
3. How many different permutations of the word "MATH" are there?
4. How many different ways can you select 2 books from a set of 10 books?
5. How many different ways can you arrange the letters in the word "ALGEBRA"?

**Tip:** Remember, the factorial function (n!) is the product of all positive integers up to n, and it's crucial for calculating permutations.

Discover how many numbers with at least three different digits can be formed using the integers 1, 2, 3, 4, 5, and 6. This problem involves combinatorics and permutations, covering the selection and arrangement of digits in numbers. Suitable for advanced high school students (Grades 10-12).

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation