Math Problem Statement

Question 1 By [ 𝑛 ] [n]we denote the set { 1 , … , 𝑛 } {1,…,n}. A function 𝑓 : [ π‘š ] β†’ [ 𝑛 ] f:[m]β†’[n] is called monotone if 𝑓 ( 𝑖 ) ≀ 𝑓 ( 𝑗 ) f(i)≀f(j)whenever 𝑖 < 𝑗 i<j. Let 𝑆 ( π‘š , 𝑛 ) S(m,n) be the number of monotone injective functions from [ π‘š ] [m] to [ 𝑛 ] [n]. What is the number of monotone injective functions from [ 10 ] [10] to [ 20 ] [20]?

Solution

We are asked to find the number of monotone injective functions from [10][10] to [20][20], where [n][n] is the set {1,2,…,n}\{1, 2, \dots, n\}, and a function f:[m]β†’[n]f: [m] \to [n] is monotone if for any i<ji < j, f(i)≀f(j)f(i) \leq f(j). Additionally, the function is injective, meaning f(i)β‰ f(j)f(i) \neq f(j) for all iβ‰ ji \neq j.

Understanding the problem

  1. The function ff is monotone and injective, meaning it must map smaller inputs to smaller outputs in a strictly increasing manner.
  2. This implies that the function is a strictly increasing function, i.e., f(i)<f(j)f(i) < f(j) whenever i<ji < j.
  3. The number of monotone injective functions from [m][m] to [n][n] is equivalent to choosing mm distinct elements from [n][n] and then ordering them in increasing order (which is done automatically by the monotonicity requirement).

Step-by-step solution

The problem now reduces to counting how many ways we can choose 10 elements from the set [20][20] (since the monotonicity enforces a strict order).

This is a simple combinatorics problem of selecting 10 elements from a set of 20, which is given by the binomial coefficient:

S(10,20)=(2010)S(10, 20) = \binom{20}{10}

Calculate the binomial coefficient

The formula for the binomial coefficient is:

(nk)=n!k!(nβˆ’k)!\binom{n}{k} = \frac{n!}{k!(n-k)!}

In this case:

(2010)=20!10!β‹…10!\binom{20}{10} = \frac{20!}{10! \cdot 10!}

We can calculate this value.

(2010)=184,756\binom{20}{10} = 184,756

Conclusion

The number of monotone injective functions from [10][10] to [20][20] is:

S(10,20)=184,756S(10, 20) = 184,756

Let me know if you'd like further details or have any questions!

Here are 5 related questions for further exploration:

  1. How do you calculate the number of injective functions if monotonicity is not required?
  2. What is the number of monotone injective functions from [5][5] to [15][15]?
  3. How does the binomial coefficient change if you increase the size of the sets?
  4. How can you generalize this concept for non-injective monotone functions?
  5. What is the significance of monotone functions in real-world applications?

Tip: Binomial coefficients often arise in combinatorics, especially when counting ways to choose items from a set.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Combinatorics
Injective Functions
Monotonicity

Formulas

Binomial Coefficient: C(n, k) = n! / (k!(n-k)!)

Theorems

Binomial Theorem

Suitable Grade Level

Undergraduate Mathematics