Math Problem Statement

Exam 2.pdf

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show a counter example for 1a

Solution

To find a counterexample for part 1a, let’s examine why this structure fails to be a vector space. We need to check if this modified version of R2\mathbb{R}^2 (with the non-standard addition defined as [ab]+[cd]=[acbd]\begin{bmatrix} a \\ b \end{bmatrix} + \begin{bmatrix} c \\ d \end{bmatrix} = \begin{bmatrix} a - c \\ b - d \end{bmatrix}) fails any of the vector space axioms.

One of the critical axioms of a vector space is that addition must be commutative: u+v=v+uu,vR2\vec{u} + \vec{v} = \vec{v} + \vec{u} \quad \forall \vec{u}, \vec{v} \in \mathbb{R}^2

With the given definition of addition, however, we can find a counterexample:

  1. Select two vectors in R2\mathbb{R}^2, say: u=[12]andv=[34]\vec{u} = \begin{bmatrix} 1 \\ 2 \end{bmatrix} \quad \text{and} \quad \vec{v} = \begin{bmatrix} 3 \\ 4 \end{bmatrix}

  2. Compute u+v\vec{u} + \vec{v} using the given definition: u+v=[12]+[34]=[1324]=[22]\vec{u} + \vec{v} = \begin{bmatrix} 1 \\ 2 \end{bmatrix} + \begin{bmatrix} 3 \\ 4 \end{bmatrix} = \begin{bmatrix} 1 - 3 \\ 2 - 4 \end{bmatrix} = \begin{bmatrix} -2 \\ -2 \end{bmatrix}

  3. Compute v+u\vec{v} + \vec{u} using the same addition rule: v+u=[34]+[12]=[3142]=[22]\vec{v} + \vec{u} = \begin{bmatrix} 3 \\ 4 \end{bmatrix} + \begin{bmatrix} 1 \\ 2 \end{bmatrix} = \begin{bmatrix} 3 - 1 \\ 4 - 2 \end{bmatrix} = \begin{bmatrix} 2 \\ 2 \end{bmatrix}

  4. Observe the result: u+v=[22][22]=v+u\vec{u} + \vec{v} = \begin{bmatrix} -2 \\ -2 \end{bmatrix} \neq \begin{bmatrix} 2 \\ 2 \end{bmatrix} = \vec{v} + \vec{u}

Since u+vv+u\vec{u} + \vec{v} \neq \vec{v} + \vec{u}, this addition operation is not commutative, which violates the axioms required for a vector space. Therefore, this serves as a counterexample to show that the given set with this addition is not a vector space.


Do you have any questions or would you like more details? Here are some related questions to expand on this topic:

  1. What other vector space axioms could be checked for failure in this structure?
  2. Could an alternative definition of addition make this a vector space?
  3. How would scalar multiplication be affected if a different addition rule is chosen?
  4. Can you provide examples of common vector spaces that satisfy all vector space properties?
  5. What is the impact of non-standard operations on the structure of mathematical objects like vector spaces?

Tip: When verifying if a set and operations form a vector space, always begin by checking the axioms of vector addition and scalar multiplication, as these often reveal whether the structure can indeed be classified as a vector space.

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Math Problem Analysis

Mathematical Concepts

Vector Spaces
Counterexamples
Non-standard Operations

Formulas

Addition operation for \(\mathbb{R}^2\): \(\begin{bmatrix} a \\ b \end{bmatrix} + \begin{bmatrix} c \\ d \end{bmatrix} = \begin{bmatrix} a - c \\ b - d \end{bmatrix}\)

Theorems

Vector Space Axioms
Commutative Property of Addition

Suitable Grade Level

Undergraduate Level