Math Problem Statement
Find counter-example: if A and B are sets, then |A+B|=|A|+|A|
Solution
The statement is incorrect, and we can find a counterexample by interpreting "A + B" in different ways, such as the union of two sets. The correct interpretation of the equation should be clarified. However, assuming refers to the union of the sets and , the correct relation would be:
This formula accounts for the overlap between sets and . So, the given equation is only true when and are disjoint (i.e., ).
Counterexample:
Let:
Now,
- , so .
Clearly, and . Hence, , providing a counterexample to the given statement.
Would you like more details on how we find intersections and unions of sets?
Here are 5 questions to deepen your understanding:
- How does the formula for the union of two sets change when they overlap?
- Can we extend this reasoning to more than two sets? How?
- What happens when and are subsets of each other?
- How can Venn diagrams help visualize these concepts?
- How would the result change if we took the Cartesian product instead of the union?
Tip: Always check for overlaps between sets when calculating their union, as it impacts the total number of distinct elements.
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Math Problem Analysis
Mathematical Concepts
Set Theory
Union of Sets
Intersection of Sets
Formulas
|A ∪ B| = |A| + |B| - |A ∩ B|
Theorems
Principle of Inclusion-Exclusion
Suitable Grade Level
Grades 9-12