Math Problem Statement

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Show that the set E = {2k : k ∈ N} is countably infinite.

Solution

The image provided contains the following problem from an exercise sheet:

Problem 13: "Show that the set E={2k:kN}E = \{2k : k \in \mathbb{N}\} is countably infinite."

Solution Outline:

To show that the set E={2k:kN}E = \{2k : k \in \mathbb{N}\} is countably infinite, we need to demonstrate two key points:

  1. The set EE is infinite: This requires us to show that there is no bound on the size of the set, i.e., it has infinitely many elements.

  2. The set EE is countable: This means that there exists a one-to-one correspondence (a bijection) between the set EE and the set of natural numbers N\mathbb{N}.


Step 1: Showing that EE is infinite

The set EE consists of even natural numbers, because each element of EE is of the form 2k2k where kNk \in \mathbb{N}. As kk increases without bound (since N\mathbb{N} is infinite), the values 2k2k also increase without bound. Therefore, the set EE contains an infinite number of elements, since there is no upper limit on the values of kk in N\mathbb{N}.

Step 2: Showing that EE is countable

To show that EE is countable, we need to construct a bijection between N\mathbb{N} (the set of natural numbers) and EE (the set of even natural numbers). Define a function f:NEf : \mathbb{N} \to E by the rule:

f(k)=2kfor allkN.f(k) = 2k \quad \text{for all} \quad k \in \mathbb{N}.

  • This function is injective (one-to-one) because if f(k1)=f(k2)f(k_1) = f(k_2), then 2k1=2k22k_1 = 2k_2, which implies k1=k2k_1 = k_2.

  • The function is also surjective (onto) because for every element eEe \in E, we can find a corresponding kNk \in \mathbb{N} such that e=2ke = 2k. Specifically, for any eEe \in E, ee must be of the form 2k2k for some kNk \in \mathbb{N}, so f(k)=ef(k) = e.

Since the function ff is both injective and surjective, it is a bijection between N\mathbb{N} and EE.

Conclusion:

Since there exists a bijection between N\mathbb{N} and EE, the set E={2k:kN}E = \{2k : k \in \mathbb{N}\} is countably infinite.


Would you like further clarification on any part of this explanation?

Here are five related questions that can extend your understanding:

  1. How would you prove that the set of odd numbers is countably infinite?
  2. What is the definition of a countably infinite set in mathematical terms?
  3. Can you describe another example of a set that is countably infinite?
  4. What is the difference between countably infinite and uncountably infinite sets?
  5. How can we extend this concept to show that all subsets of natural numbers are countable?

Tip: When proving a set is countable, finding a bijection with N\mathbb{N} is a common strategy to establish the countability.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Countability
Infinity

Formulas

f(k) = 2k for k ∈ N

Theorems

Bijection between Natural Numbers and Even Numbers
Countably Infinite Sets

Suitable Grade Level

Undergraduate Mathematics