Math Problem Statement

The number of three digit number which are not divisible by 45 but divisible by either four or three

Solution

To solve the problem, we need to determine how many three-digit numbers are:

  1. Not divisible by 45, and
  2. Divisible by either 3 or 4.

Step 1: Count the total number of three-digit numbers.

The three-digit numbers range from 100 to 999. So, the total number of three-digit numbers is: 999100+1=900999 - 100 + 1 = 900

Step 2: Count the number of three-digit numbers divisible by 45.

A number divisible by 45 must be divisible by both 5 and 9 (since 45=5×945 = 5 \times 9). The least three-digit number divisible by 45 is 105, and the greatest is 990.

To find how many three-digit numbers are divisible by 45, we use: Number of terms=Last termFirst termCommon difference+1\text{Number of terms} = \frac{\text{Last term} - \text{First term}}{\text{Common difference}} + 1 =99010545+1=88545+1=19+1=20= \frac{990 - 105}{45} + 1 = \frac{885}{45} + 1 = 19 + 1 = 20 So, there are 20 three-digit numbers divisible by 45.

Step 3: Count the number of three-digit numbers divisible by either 3 or 4.

  • Divisible by 3: The smallest three-digit number divisible by 3 is 102, and the largest is 999. Using the same formula as above: Number of terms=9991023+1=8973+1=299+1=300\text{Number of terms} = \frac{999 - 102}{3} + 1 = \frac{897}{3} + 1 = 299 + 1 = 300
  • Divisible by 4: The smallest three-digit number divisible by 4 is 100, and the largest is 996. Using the same formula: Number of terms=9961004+1=8964+1=224+1=225\text{Number of terms} = \frac{996 - 100}{4} + 1 = \frac{896}{4} + 1 = 224 + 1 = 225

Step 4: Use the principle of inclusion-exclusion to count the numbers divisible by either 3 or 4.

Some numbers are divisible by both 3 and 4 (i.e., divisible by 12). The smallest three-digit number divisible by 12 is 108, and the largest is 996. The count of such numbers is: Number of terms=99610812+1=88812+1=74+1=75\text{Number of terms} = \frac{996 - 108}{12} + 1 = \frac{888}{12} + 1 = 74 + 1 = 75 Now, the number of three-digit numbers divisible by either 3 or 4 is: 300+22575=450300 + 225 - 75 = 450

Step 5: Subtract the numbers divisible by 45 from those divisible by either 3 or 4.

Numbers divisible by 45 are included in the 450 numbers divisible by either 3 or 4. We need to subtract these 20 numbers: 45020=430450 - 20 = 430

So, there are 430 three-digit numbers that are not divisible by 45 but are divisible by either 3 or 4.


Would you like more details on any step, or do you have further questions? Here are five related problems to explore:

  1. How many three-digit numbers are divisible by 5 but not by 9?
  2. What is the total number of three-digit numbers divisible by both 6 and 8?
  3. How many three-digit numbers are not divisible by 3 but divisible by 7?
  4. Find the number of three-digit numbers divisible by either 2, 3, or 5.
  5. How many four-digit numbers are divisible by 45 but not by 90?

Tip: Understanding the principle of inclusion-exclusion can greatly simplify problems involving multiple conditions.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Divisibility
Inclusion-Exclusion Principle

Formulas

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Theorems

Inclusion-Exclusion Principle

Suitable Grade Level

Grades 6-8