Math Problem Statement

In the 3 base number system, how many numbers are there in the sequence 0, 1, 2, 10, 11, 12, 20, ..., 10000?

Solution

The problem asks how many numbers are in the sequence 0,1,2,10,11,12,20,,100000, 1, 2, 10, 11, 12, 20, \dots, 10000 when written in base 3.


Key Insights:

  1. Base 3 System:

    • The numbers are expressed in base 3, where the digits can only be 0,1,20, 1, 2.
  2. General Form:

    • In base 3, a number with nn digits can have up to 3n3^n different values (from 00 to 3n13^n - 1).
  3. Sequence Stops at 1000010000 (in base 3):

    • The largest number in the sequence is 1000010000 in base 3, which is 34=813^4 = 81 in decimal.
  4. Counting All Numbers:

    • The sequence starts at 00 and goes up to 1000010000 (inclusive). This corresponds to 81+1=8281 + 1 = 82 numbers (since 00 is included).

Conclusion:

There are 82 numbers in this sequence.


Would you like more details or further explanations on any part of this solution?


Follow-up Questions:

  1. What is the significance of the base 3 system compared to base 10?
  2. How is the number 1000010000 in base 3 converted to decimal?
  3. Can this method be applied to any other base system?
  4. What are the first 10 numbers in base 3, and how do they compare to base 10?
  5. How can you quickly identify the number of digits needed to represent a given number in base 3?

Tip:

When working with numbers in different bases, practice converting them between base 10 and the desired base to build familiarity.

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Math Problem Analysis

Mathematical Concepts

Base Systems
Counting Numbers
Exponential Growth

Formulas

Number of values in base-n = n^k, where k is the number of digits

Theorems

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Suitable Grade Level

Grades 6-8