Math Problem Statement
Solution
Let's analyze and solve the questions in the image you provided.
Given functions:
- Cost function:
- Revenue function: where represents the number of items produced and sold.
Now let's solve each part:
i) How many items must be produced so that the cost is less than 4500?
We need to find such that the cost .
Setting the inequality: Solving for : Thus, the number of items must be less than 100 for the cost to be less than 4500.
ii) What will be the minimum quantities of items to be sold so that the revenue is greater than or equal to 10,500 rupees?
We need to solve for such that .
Setting the inequality: Solving for : Thus, the minimum number of items to be sold for revenue to be greater than or equal to 10500 is 200 items.
iii) If the number of items sold lies between 300 to 400, then what will be the revenue?
We are asked to find the revenue when is between 300 and 400, i.e., for .
Using the revenue function :
For :
For :
So, the revenue will be between 15000 and 19500 when the number of items sold lies between 300 and 400.
OR) How many items must be sold to gain some profit?
To make a profit, the revenue must exceed the cost, i.e., .
Setting the inequality: Solving for : Thus, the company must sell more than 50 items to gain some profit.
Would you like more details on any part of this? Here are some related questions for deeper understanding:
- How would the results change if the cost function had a different fixed cost?
- What would happen to the minimum quantity required for profit if the selling price per item was lowered?
- How would you compute the break-even point for this cost and revenue system?
- What is the profit if 400 items are sold?
- How do changes in fixed cost or variable cost affect the profit margin?
Tip: When solving inequalities, always check if the solution needs to be rounded or exact, especially in real-world scenarios like production or sales.
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Math Problem Analysis
Mathematical Concepts
Linear Functions
Inequalities
Revenue and Cost Analysis
Formulas
C(x) = 15x + 3000
R(x) = 45x + 1500
Profit condition: R(x) > C(x)
Theorems
Solving inequalities
Basic profit condition
Suitable Grade Level
Grades 9-12
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