Math Problem Statement

Calculate the correlation coefficient using the given data and construct a frequency distribution table for the provided sample data.

Solution

Let's address the two tasks presented in the image:


Question 1: Correlation Coefficient

We are tasked to calculate the correlation coefficient for the given data:

Age of a Car (X)2456811
Resale Value (Y)181511875

Steps:

  1. Calculate the Mean of X and Y:

    • Mean of XX (Xˉ\bar{X}): Sum of XNumber of values\frac{\text{Sum of X}}{\text{Number of values}}
    • Mean of YY (Yˉ\bar{Y}): Sum of YNumber of values\frac{\text{Sum of Y}}{\text{Number of values}}
  2. Calculate Deviations:

    • (XXˉ)(X - \bar{X}) and (YYˉ)(Y - \bar{Y})
  3. Calculate the Products of Deviations:

    • (XXˉ)(YYˉ)(X - \bar{X})(Y - \bar{Y})
  4. Calculate Squared Deviations:

    • (XXˉ)2(X - \bar{X})^2 and (YYˉ)2(Y - \bar{Y})^2
  5. Plug into the Correlation Formula:

    • r=(XXˉ)(YYˉ)(XXˉ)2(YYˉ)2r = \frac{\sum (X - \bar{X})(Y - \bar{Y})}{\sqrt{\sum (X - \bar{X})^2 \cdot \sum (Y - \bar{Y})^2}}

Let me calculate this for you.


Question 2: Frequency Distribution Table

The provided data is: 0.5,1.0,1.5,1.0,2.0,2.5,2.0,3.0,2.5,3.5,4.0,4.5,3.0,2.5,2.0,1.0,0.5,2.5,3.0,3.5,4.5,5.0,5.5,5.0,4.0,3.0,3.5,2.0,1.5,2.0,2.5,3.5,4.0,4.5,5.5,5.0,5.0,4.0,3.0,2.0,1.0,0.5,0.5,1.5,2.5,3.5,4.50.5, 1.0, 1.5, 1.0, 2.0, 2.5, 2.0, 3.0, 2.5, 3.5, 4.0, 4.5, 3.0, 2.5, 2.0, 1.0, 0.5, 2.5, 3.0, 3.5, 4.5, 5.0, 5.5, 5.0, 4.0, 3.0, 3.5, 2.0, 1.5, 2.0, 2.5, 3.5, 4.0, 4.5, 5.5, 5.0, 5.0, 4.0, 3.0, 2.0, 1.0, 0.5, 0.5, 1.5, 2.5, 3.5, 4.5

We need to divide the data into 6 classes, starting with the first class as 0.00.90.0 - 0.9.

Steps:

  1. Define the Class Intervals:

    • 0.00.9,1.01.9,2.02.9,3.03.9,4.04.9,5.05.90.0-0.9, 1.0-1.9, 2.0-2.9, 3.0-3.9, 4.0-4.9, 5.0-5.9
  2. Tally the Frequencies:

    • Count how many values fall into each interval.
  3. Create the Frequency Distribution Table.

Let me process these for you.import pandas as pd import numpy as np

Data for Question 1 (Correlation Coefficient)

ages = np.array([2, 4, 5, 6, 8, 11]) # X values resale_values = np.array([18, 15, 11, 8, 7, 5]) # Y values

Step 1: Calculate means

mean_x = np.mean(ages) mean_y = np.mean(resale_values)

Step 2: Calculate deviations

deviation_x = ages - mean_x deviation_y = resale_values - mean_y

Step 3: Calculate product of deviations

product_deviation = deviation_x * deviation_y

Step 4: Calculate squared deviations

squared_deviation_x = deviation_x ** 2 squared_deviation_y = deviation_y ** 2

Step 5: Correlation coefficient formula

numerator = np.sum(product_deviation) denominator = np.sqrt(np.sum(squared_deviation_x) * np.sum(squared_deviation_y)) correlation_coefficient = numerator / denominator

Data for Question 2 (Frequency Distribution)

data = [ 0.5, 1.0, 1.5, 1.0, 2.0, 2.5, 2.0, 3.0, 2.5, 3.5, 4.0, 4.5, 3.0, 2.5, 2.0, 1.0, 0.5, 2.5, 3.0, 3.5, 4.5, 5.0, 5.5, 5.0, 4.0, 3.0,

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Math Problem Analysis

Mathematical Concepts

Statistics
Correlation Coefficient
Frequency Distribution

Formulas

Correlation Coefficient: r = Σ((X - X̄)(Y - Ȳ)) / √(Σ(X - X̄)^2 * Σ(Y - Ȳ)^2)
Frequency Distribution: Count data points in defined class intervals

Theorems

Basic Statistical Properties of Correlation
Concept of Frequency Distributions

Suitable Grade Level

Grades 9-12