To solve this problem, we'll apply the given transformations step by step:

Step 1: Rotate Figure ABCD 90° Clockwise

For a 90° clockwise rotation about the origin, the transformation for each point $(x, y)$ is: $(x', y') = (y, -x)$

Let’s apply this transformation to each vertex of figure ABCD:

• A(1, 2):
  $A' = (2, -1)$
• B(1, 3):
  $B' = (3, -1)$
• C(3, 5):
  $C' = (5, -3)$
• D(4, 1):
  $D' = (1, -4)$

So after the 90° clockwise rotation, the new coordinates of figure ABCD are:
$A'(2, -1), B'(3, -1), C'(5, -3), D'(1, -4)$

Step 2: Reflect the Rotated Figure over the y-axis

For a reflection over the y-axis, the transformation for each point $(x', y')$ is: $(x'', y'') = (-x', y')$

Now, apply this transformation to each rotated point:

• A'(2, -1):
  $A'' = (-2, -1)$
• B'(3, -1):
  $B'' = (-3, -1)$
• C'(5, -3):
  $C'' = (-5, -3)$
• D'(1, -4):
  $D'' = (-1, -4)$

Final Coordinates of Figure EFGH

The coordinates of figure EFGH after the transformations are: $E(-2, -1), F(-3, -1), G(-5, -3), H(-1, -4)$

Thus, the coordinates of figure EFGH are:

• $E(-2, -1)$
• $F(-3, -1)$
• $G(-5, -3)$
• $H(-1, -4)$

Do you have any questions or want more details on any of the steps?

Here are five related questions to think about:

1. What are the formulas for 90° and 180° counterclockwise rotations about the origin?
2. How would the coordinates change if the reflection were over the x-axis instead of the y-axis?
3. How does a 270° clockwise rotation affect the points compared to a 90° rotation?
4. What is the result of applying both a rotation and a reflection in reverse order?
5. How would this process change if figure ABCD were scaled before the transformations?

Tip: When rotating points, always double-check the sign changes in the coordinates to ensure accuracy.