Let's break down the problem and solve it step by step.

We have two points:

• $A(-2, 6)$
• $B(-3, 5)$

The transformations that will be applied are as follows:

1. Translation by vector $T\left( \frac{2}{3} \right)$, meaning we add 2 to the x-coordinates and subtract 3 from the y-coordinates of both points.

   For point $A(-2, 6)$: $A' = (-2 + 2, 6 - 3) = (0, 3)$

   For point $B(-3, 5)$: $B' = (-3 + 2, 5 - 3) = (-1, 2)$

2. Reflection over the line $y = -x$. To reflect a point over this line, we switch the coordinates and change their signs. In other words, the reflection of a point $(x, y)$ over the line $y = -x$ is $(-y, -x)$.

   For point $A'(0, 3)$: $A'' = (-3, 0)$

   For point $B'(-1, 2)$: $B'' = (-2, 1)$

3. Rotation by 90° clockwise. A 90° clockwise rotation transforms a point $(x, y)$ into $(y, -x)$.

   For point $A''(-3, 0)$: $A''' = (0, 3)$

   For point $B''(-2, 1)$: $B''' = (1, 2)$

So, after performing all the transformations, the final coordinates of $A$ and $B$ are:

• $A(0, 3)$
• $B(1, 2)$

Thus, the correct answer is D.

Let me know if you'd like further clarifications or details on any of the steps!

Related Questions:

1. How do you find the result of a 180° rotation?
2. What is the general formula for reflecting a point over a vertical or horizontal line?
3. How do we rotate points by angles other than 90°?
4. What are the properties of translations in coordinate geometry?
5. How do you reflect a point over an arbitrary line (not axes or $y = -x$)?

Tip: To reflect a point over the line $y = x$, simply switch the coordinates $(x, y) \to (y, x)$.