To express the equation $16^{1/4} = 2$ in logarithmic form, we apply the general rule for logarithmic transformation:

$a^b = c \quad \text{is equivalent to} \quad \log_a(c) = b$

Here, $a = 16$, $b = \frac{1}{4}$, and $c = 2$. Using the rule:

$\log_{16}(2) = \frac{1}{4}$

Thus, the logarithmic form of the equation $16^{1/4} = 2$ is:

$\log_{16}(2) = \frac{1}{4}$

Would you like more details or have any questions?

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Here are 5 related questions to further your understanding:

1. What is the logarithmic form of $27^{1/3} = 3$?
2. How would you solve $\log_2(x) = 3$?
3. What is the exponential form of $\log_5(25) = 2$?
4. How does the base change formula for logarithms work?
5. How would you simplify $\log_8(2)$ using logarithmic properties?

Tip: Remember, logarithms are the inverse of exponentiation. Understanding this relationship helps solve many equations quickly.