To convert the equation $3y + 18x = 0$ to slope-intercept form, which is $y = mx + b$, follow these steps:

1. Start with the given equation: $3y + 18x = 0$

2. Isolate $y$ by subtracting $18x$ from both sides: $3y = -18x$

3. Divide both sides by 3 to solve for $y$: $y = -6x$

Now the equation is in slope-intercept form $y = -6x + 0$, where:

• The slope $m = -6$
• The y-intercept $b = 0$

So, the slope-intercept form is: $y = -6x$

Would you like more details or have any questions about this process? Here's some additional related info:

1. What is the slope of the line in the equation $y = -6x + 3$?
2. How do you graph a line using slope-intercept form?
3. What happens if the y-intercept is not 0 in slope-intercept form?
4. How do you convert a linear equation in standard form to slope-intercept form?
5. What is the slope-intercept form of the equation $5x + 2y = 10$?

Tip: To convert equations to slope-intercept form, always aim to isolate $y$ on one side of the equation.