Math Problem Statement

convert the equation 4x^2+9y^2-36x+18y+36=0 to standard form

Solution

To convert the equation 4x2+9y236x+18y+36=04x^2 + 9y^2 - 36x + 18y + 36 = 0 to its standard form, we will complete the square for both the xx and yy terms.

Step 1: Group the xx and yy terms together

4x236x+9y2+18y=364x^2 - 36x + 9y^2 + 18y = -36

Step 2: Factor out the coefficients of x2x^2 and y2y^2 from the grouped terms

4(x29x)+9(y2+2y)=364(x^2 - 9x) + 9(y^2 + 2y) = -36

Step 3: Complete the square for both xx and yy

  • For xx, complete the square inside the parentheses: x29xcan be written as(x92)2(92)2x^2 - 9x \quad \text{can be written as} \quad (x - \frac{9}{2})^2 - \left(\frac{9}{2}\right)^2 So, x29x=(x92)2814x^2 - 9x = (x - \frac{9}{2})^2 - \frac{81}{4}
  • For yy, complete the square inside the parentheses: y2+2ycan be written as(y+1)21y^2 + 2y \quad \text{can be written as} \quad (y + 1)^2 - 1 So, y2+2y=(y+1)21y^2 + 2y = (y + 1)^2 - 1

Step 4: Substitute the completed squares back into the equation

[ 4\left[(x - \frac{9}{2})^2 - \frac{81}{4}\right] + 9\left[(y + 1)^2 - 1\right] = -36 ] Expand and simplify: 4(x92)281+9(y+1)29=364(x - \frac{9}{2})^2 - 81 + 9(y + 1)^2 - 9 = -36 4(x92)2+9(y+1)290=364(x - \frac{9}{2})^2 + 9(y + 1)^2 - 90 = -36

Step 5: Move constants to the other side

4(x92)2+9(y+1)2=544(x - \frac{9}{2})^2 + 9(y + 1)^2 = 54

Step 6: Divide by 54 to normalize the equation

4(x92)254+9(y+1)254=1\frac{4(x - \frac{9}{2})^2}{54} + \frac{9(y + 1)^2}{54} = 1

Simplify the coefficients: (x92)2272+(y+1)26=1\frac{(x - \frac{9}{2})^2}{\frac{27}{2}} + \frac{(y + 1)^2}{6} = 1 Which simplifies to: (x92)2272+(y+1)26=1\frac{(x - \frac{9}{2})^2}{\frac{27}{2}} + \frac{(y + 1)^2}{6} = 1

Thus, the equation in standard form is: (x92)2272+(y+1)26=1\frac{(x - \frac{9}{2})^2}{\frac{27}{2}} + \frac{(y + 1)^2}{6} = 1

This is the standard form of the ellipse.

Would you like more details or have any questions about this process?

Here are some related questions you might consider:

  1. What are the center, axes, and orientation of the ellipse?
  2. How do you determine the lengths of the major and minor axes?
  3. How does completing the square work in general?
  4. What is the geometric interpretation of this ellipse?
  5. How would this process change if the original equation were for a hyperbola?

Tip: Completing the square is a key technique in transforming quadratic equations into standard forms. It's especially useful in conic sections.

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Math Problem Analysis

Mathematical Concepts

Algebra
Ellipses
Completing the Square
Conic Sections

Formulas

Equation of an ellipse: (x-h)^2/a^2 + (y-k)^2/b^2 = 1
Completing the square: (x - p)^2 = x^2 - 2px + p^2

Theorems

Completing the Square
Standard Form of Ellipse

Suitable Grade Level

Grades 10-12