The equation provided is:

$\frac{1}{16} = 2^{-4}$

To express this equation in logarithmic form, recall that the general logarithmic form is:

$\log_b(x) = y \quad \text{is equivalent to} \quad b^y = x$

In this case, $b = 2$, $x = \frac{1}{16}$, and $y = -4$.

So, the logarithmic form is:

$\log_2 \left( \frac{1}{16} \right) = -4$

Would you like a more detailed explanation of this process or have other questions? Here are some related questions for further exploration:

1. What are the properties of logarithms?
2. How can you convert logarithmic equations into exponential form?
3. What are common logarithms and natural logarithms, and how do they differ from other bases?
4. Can you solve for an unknown in logarithmic form?
5. How do you apply logarithmic rules to simplify expressions?

Tip: Remember that logarithmic and exponential functions are inverses of each other!