Let's first solve part A by rewriting the equation $-9x - 10y = -3$ in the slope-intercept form $y = mx + b$.

Part A:

Starting with the given equation: $-9x - 10y = -3$

1. Isolate $y$ on one side: $-10y = 9x - 3$

2. Divide both sides by $-10$ to solve for $y$: $y = \frac{9x - 3}{-10}$

3. Simplify the equation: $y = -\frac{9}{10}x + \frac{3}{10}$

Thus, the equation in slope-intercept form is: $y = -\frac{9}{10}x + \frac{3}{10}$

In this form, $m = -\frac{9}{10}$ (the slope) and $b = \frac{3}{10}$ (the y-intercept).

Part B:

Now, use the equation from part A to find the $y$-coordinate when $x = -10$.

Substitute $x = -10$ into the equation: $y = -\frac{9}{10}(-10) + \frac{3}{10}$

Simplify: $y = \frac{90}{10} + \frac{3}{10} = 9 + \frac{3}{10} = 9 + 0.3 = 9.3$

So, the ordered pair is: $(-10, 9.3)$

If you prefer the fraction form, $9.3 = \frac{93}{10}$, so the ordered pair is $(-10, \frac{93}{10})$.

Summary:

A) The equation is: $y = -\frac{9}{10}x + \frac{3}{10}$ with $m = -\frac{9}{10}$ and $b = \frac{3}{10}$.

B) The ordered pair when $x = -10$ is: $(-10, 9.3) \text{ or } (-10, \frac{93}{10})$

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Do you have any questions or would you like further details?

Here are 5 related questions to expand on this concept:

1. How do you find the slope of a line given two points?
2. What does the slope represent in a real-world context?
3. How do you graph a line using the slope and y-intercept?
4. How can you rewrite an equation in standard form given the slope-intercept form?
5. What are the conditions for two lines to be parallel or perpendicular?

Tip: When converting an equation to slope-intercept form, focus on isolating $y$ on one side.