Math Problem Statement

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Part 1

Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance has a melting point of

negative 45.67 degrees Upper C−45.67°C

and a boiling point of

310.21 degrees Upper C310.21°C.

What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid​ state? (Hint:

Upper C equals five ninths left parenthesis Upper F minus 32 right parenthesisC=59(F−32)​)

Express the range as an inequality.

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Part 1

Let x represent the temperature in degrees Fahrenheit. What is the range of temperatures for which this substance is not in a liquid​ state?

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Solution

To find the range of temperatures in degrees Fahrenheit where the substance is not in a liquid state, we'll follow these steps:

  1. Convert the melting point and boiling point from Celsius to Fahrenheit using the formula: C=59(F32)C = \frac{5}{9}(F - 32) Solving for FF: F=95C+32F = \frac{9}{5}C + 32

  2. Determine the range where the temperature is not in a liquid state, which occurs when the temperature is below the melting point or above the boiling point.

Let's calculate this step by step.

Step 1: Convert Melting Point from Celsius to Fahrenheit

  • Given: Melting point = 45.67C-45.67^\circ \text{C} F=95(45.67)+32F = \frac{9}{5}(-45.67) + 32

Step 2: Convert Boiling Point from Celsius to Fahrenheit

  • Given: Boiling point = 310.21C310.21^\circ \text{C} F=95(310.21)+32F = \frac{9}{5}(310.21) + 32

Step 3: Define the Range Where the Substance is Not in a Liquid State

The substance will be in a non-liquid state when:

  • The temperature is less than the melting point or greater than the boiling point.

Let's calculate the exact values.The conversion of the temperature points to Fahrenheit gives us the following results:

  • The melting point is 50.21F-50.21^\circ \text{F}.
  • The boiling point is 590.38F590.38^\circ \text{F}.

Step 3: Define the Range of Temperatures

The substance will be not in a liquid state when:

  1. The temperature is below 50.21F-50.21^\circ \text{F}, or
  2. The temperature is above 590.38F590.38^\circ \text{F}.

Therefore, the range of temperatures where the substance is not in a liquid state is: x<50.21orx>590.38x < -50.21 \quad \text{or} \quad x > 590.38 where xx represents the temperature in degrees Fahrenheit.

Would you like more details or have any further questions?

Here are 5 related questions to deepen your understanding:

  1. How would the inequality change if the melting and boiling points were reversed?
  2. What happens to the state of the substance exactly at the melting or boiling points?
  3. How would you express this temperature range on a number line?
  4. Can you convert these temperature ranges back to Celsius?
  5. What physical changes occur to substances at their melting and boiling points?

Tip: When converting temperatures between Celsius and Fahrenheit, always remember to apply the correct formula: F=95C+32F = \frac{9}{5}C + 32.

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Math Problem Analysis

Mathematical Concepts

Temperature Conversion
Inequalities
Range of Values

Formulas

C = 5/9(F - 32)
F = 9/5(C) + 32

Theorems

Linear Equations
Temperature Conversion between Celsius and Fahrenheit

Suitable Grade Level

Grades 8-10