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To convert the base-10 number 248 to a base-6 numeral, we need to repeatedly divide the number by 6 and keep track of the remainders. Here's the step-by-step process:

1. Divide 248 by 6:
   \[
   248 \div 6 = 41 \text{ remainder } 2
   \]
   So, the first digit from the right is 2.

2. Divide 41 by 6:
   \[
   41 \div 6 = 6 \text{ remainder } 5
   \]
   The next digit from the right is 5.

3. Divide 6 by 6:
   \[
   6 \div 6 = 1 \text{ remainder } 0
   \]
   The next digit is 0.

4. Finally, divide 1 by 6:
   \[
   1 \div 6 = 0 \text{ remainder } 1
   \]
   The last digit is 1.

Now, putting all the remainders together from last to first, we get:

\[
248_{10} = 1052_6
\]

Let me know if you'd like further details!

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Here are some additional related questions for practice:
1. How would you convert \( 540_{10} \) to base-6?
2. What is the base-6 representation of \( 99_{10} \)?
3. How do you convert a base-6 number back to base-10?
4. Can you explain the steps to convert \( 134_{10} \) to base-6?
5. What is the base-6 representation of \( 350_{10} \)?

**Tip**: Always check the remainders carefully during conversion; they form the digits of the new base system from right to left!

Convert the following base-ten numeral to a base-six numeral. 248ten = ______six

Learn how to convert the base-10 number 248 into a base-6 numeral with a detailed step-by-step solution. This problem explores concepts related to number systems and base conversions, making it ideal for students in Grades 6-8.

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