Math Problem Statement

Convert the following base-ten numeral to a base-six numeral. 248ten = ______six

Solution

To convert the base-10 number 248 to a base-6 numeral, we need to repeatedly divide the number by 6 and keep track of the remainders. Here's the step-by-step process:

  1. Divide 248 by 6: 248÷6=41 remainder 2248 \div 6 = 41 \text{ remainder } 2 So, the first digit from the right is 2.

  2. Divide 41 by 6: 41÷6=6 remainder 541 \div 6 = 6 \text{ remainder } 5 The next digit from the right is 5.

  3. Divide 6 by 6: 6÷6=1 remainder 06 \div 6 = 1 \text{ remainder } 0 The next digit is 0.

  4. Finally, divide 1 by 6: 1÷6=0 remainder 11 \div 6 = 0 \text{ remainder } 1 The last digit is 1.

Now, putting all the remainders together from last to first, we get:

24810=10526248_{10} = 1052_6

Let me know if you'd like further details!


Here are some additional related questions for practice:

  1. How would you convert 54010540_{10} to base-6?
  2. What is the base-6 representation of 991099_{10}?
  3. How do you convert a base-6 number back to base-10?
  4. Can you explain the steps to convert 13410134_{10} to base-6?
  5. What is the base-6 representation of 35010350_{10}?

Tip: Always check the remainders carefully during conversion; they form the digits of the new base system from right to left!

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Math Problem Analysis

Mathematical Concepts

Number Systems
Base Conversion

Formulas

Repeated division by the base formula for base conversion

Theorems

None applicable in this specific problem

Suitable Grade Level

Grades 6-8