A motorcyclist who weighs 150 lbs accelerates his 200 kg motorcycle at a rate of 65 ft/s2 over a distance of 100 yards in 5 seconds. Compute the acceleration in m/s2.  Round your answer to the nearest tenth.

To convert the given acceleration from feet per second squared (\( \text{ft/s}^2 \)) to meters per second squared (\( \text{m/s}^2 \)), follow these steps:

1. **Conversion factor:**

   \( 1 \, \text{foot} = 0.3048 \, \text{meters} \)

2. **Convert the acceleration:**

   Given the acceleration is \( 65 \, \text{ft/s}^2 \):

   \[
   65 \, \text{ft/s}^2 \times 0.3048 \, \frac{\text{m}}{\text{ft}}
   \]

3. **Calculate the result:**

   \[
   65 \times 0.3048 = 19.812 \, \text{m/s}^2
   \]

4. **Round to the nearest tenth:**

   \[
   19.812 \approx 19.8 \, \text{m/s}^2
   \]

Thus, the acceleration in meters per second squared, rounded to the nearest tenth, is \( 19.8 \, \text{m/s}^2 \).

Would you like more details on the conversion process or have any further questions?

Here are some additional questions for further exploration:
1. How do you convert distance from yards to meters?
2. What are the units of acceleration?
3. How is acceleration related to force and mass?
4. How do you calculate the distance traveled under constant acceleration?
5. What is the difference between speed and velocity?
6. How do you calculate the final velocity given initial velocity, acceleration, and time?
7. How is acceleration due to gravity different on Earth compared to other planets?
8. How do you interpret the significance of the acceleration value in practical scenarios?

**Tip:** When converting units, always write down the conversion factor clearly to avoid any mistakes in the calculation.

Learn how to convert acceleration from feet per second squared (ft/s²) to meters per second squared (m/s²) using a detailed step-by-step solution. This problem involves physics concepts like kinematics and unit conversion, suitable for students in Grades 10-12.

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