Math Problem Statement

put -2(x-3)(x+1) in standard form

Solution

To put 2(x3)(x+1)-2(x - 3)(x + 1) in standard form, we’ll expand it by distributing and simplifying.

Step 1: Expand (x3)(x+1)(x - 3)(x + 1)

(x3)(x+1)=x2+x3x3=x22x3(x - 3)(x + 1) = x^2 + x - 3x - 3 = x^2 - 2x - 3

Step 2: Distribute 2-2 across each term

2(x22x3)=2x2+4x+6-2(x^2 - 2x - 3) = -2x^2 + 4x + 6

Final Answer

The expression in standard form is: 2x2+4x+6-2x^2 + 4x + 6

Would you like more details or have any questions?


Here are five related questions to explore further:

  1. How do we identify the vertex of the quadratic function 2x2+4x+6-2x^2 + 4x + 6?
  2. What are the roots of the function 2x2+4x+6=0-2x^2 + 4x + 6 = 0?
  3. How does the coefficient of x2x^2 affect the shape of the parabola?
  4. How would the expression change if we factored it back?
  5. How can we find the maximum or minimum value of this quadratic function?

Tip: When converting from factored to standard form, expanding and simplifying each step ensures accuracy.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations

Formulas

Standard form of a quadratic equation: ax^2 + bx + c

Theorems

Distributive Property
Polynomial Expansion

Suitable Grade Level

Grades 9-11