To convert the equation \(12x + 2y = -18\) into slope-intercept form \(y = mx + b\), follow these steps:

1. Start with the original equation: 
   \[
   12x + 2y = -18
   \]

2. Subtract \(12x\) from both sides to isolate the \(y\)-term:
   \[
   2y = -12x - 18
   \]

3. Divide every term by 2 to solve for \(y\):
   \[
   y = -6x - 9
   \]

So, the equation in slope-intercept form is:
\[
y = -6x - 9
\]

The slope \(m\) is \(-6\), and the y-intercept \(b\) is \(-9\).

Would you like more details or have any questions?

Here are 5 related questions:
1. What is the slope of a line parallel to \(y = -6x - 9\)?
2. How do you graph \(y = -6x - 9\)?
3. What is the slope-intercept form of the equation \(8x + 4y = 20\)?
4. How do you find the y-intercept of a line from an equation?
5. How do you convert an equation from slope-intercept form to standard form?

**Tip:** The slope in the slope-intercept form \(y = mx + b\) shows the steepness and direction of the line, while \(b\) tells you where the line crosses the y-axis.

Learn how to convert the linear equation 12x + 2y = -18 into slope-intercept form y = mx + b. This tutorial covers key algebraic concepts such as isolating the y-term and identifying the slope and y-intercept. Suitable for students in Grades 8-10.

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