Math Problem Statement

Check whether the series is convergent or not using suitable method for each of the following problems: (n^2)/(n^3 - n^2 + 1)

Solution

To determine whether the series

n=1n2n3n2+1\sum_{n=1}^{\infty} \frac{n^2}{n^3 - n^2 + 1}

is convergent or not, we can apply the Limit Comparison Test or Asymptotic Analysis.

Step 1: Simplify the general term

First, let's examine the asymptotic behavior of the term n2n3n2+1\frac{n^2}{n^3 - n^2 + 1} as nn \to \infty.

For large nn, the term n3n^3 will dominate in the denominator, so we approximate:

n3n2+1n3for large n.n^3 - n^2 + 1 \sim n^3 \quad \text{for large } n.

Thus, the general term behaves like:

n2n3n2+1n2n3=1n.\frac{n^2}{n^3 - n^2 + 1} \sim \frac{n^2}{n^3} = \frac{1}{n}.

Step 2: Use the Limit Comparison Test

The term 1n\frac{1}{n} is similar to the harmonic series, which is known to diverge. So, we use the Limit Comparison Test with the harmonic series 1n\sum \frac{1}{n}.

We compute the limit of the ratio of the terms:

limnn2n3n2+11n=limnn2n3n2+1×n=limnn3n3n2+1.\lim_{n \to \infty} \frac{\frac{n^2}{n^3 - n^2 + 1}}{\frac{1}{n}} = \lim_{n \to \infty} \frac{n^2}{n^3 - n^2 + 1} \times n = \lim_{n \to \infty} \frac{n^3}{n^3 - n^2 + 1}.

Simplifying this expression:

limnn3n3n2+1=limn111n+1n3=1.\lim_{n \to \infty} \frac{n^3}{n^3 - n^2 + 1} = \lim_{n \to \infty} \frac{1}{1 - \frac{1}{n} + \frac{1}{n^3}} = 1.

Since the limit is a positive finite number (1), by the Limit Comparison Test, the given series behaves similarly to the harmonic series.

Step 3: Conclusion

The harmonic series 1n\sum \frac{1}{n} diverges. Therefore, by the Limit Comparison Test, the given series:

n=1n2n3n2+1\sum_{n=1}^{\infty} \frac{n^2}{n^3 - n^2 + 1}

diverges as well.


Would you like further details on any part of this solution? Here are some related questions you might find interesting:

  1. How do we apply the Integral Test to determine convergence of a series?
  2. What is the Comparison Test, and how is it different from the Limit Comparison Test?
  3. Can a series converge if its general term does not approach zero?
  4. How do we handle series with factorial terms (e.g., n!nn\sum \frac{n!}{n^n})?
  5. What are the common methods to prove the convergence of series involving powers of nn?

Tip: When analyzing series, always start by comparing the given term to simpler series whose convergence behavior is already known (e.g., geometric, p-series).

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Math Problem Analysis

Mathematical Concepts

Series Convergence
Limit Comparison Test
Asymptotic Analysis
Harmonic Series

Formulas

Limit Comparison Test
Asymptotic Behavior of n^2 / (n^3 - n^2 + 1)

Theorems

Limit Comparison Test
Harmonic Series Divergence

Suitable Grade Level

College Level