Math Problem Statement

prove the series Σ(-1)^n-1.cos^2 nx/ns(sqrt(n))

Solution

To prove the convergence of the series

n=1(1)n1cos2(nx)nn,\sum_{n=1}^{\infty} \frac{(-1)^{n-1} \cos^2(nx)}{n \sqrt{n}},

we need to investigate its convergence properties using appropriate convergence tests, such as the Alternating Series Test, the Absolute Convergence Test, or other suitable methods.

Step 1: Analyzing the General Term

The general term of the series is given by:

an=(1)n1cos2(nx)nn.a_n = \frac{(-1)^{n-1} \cos^2(nx)}{n \sqrt{n}}.

The sequence alternates in sign due to the (1)n1(-1)^{n-1} term, and the magnitude of the term is cos2(nx)nn\frac{\cos^2(nx)}{n \sqrt{n}}.

Step 2: Testing Absolute Convergence

To test absolute convergence, we examine the series without the alternating sign:

n=1an=n=1cos2(nx)nn.\sum_{n=1}^{\infty} \left| a_n \right| = \sum_{n=1}^{\infty} \frac{\cos^2(nx)}{n \sqrt{n}}.

Since cos2(nx)\cos^2(nx) oscillates between 0 and 1, we have:

0cos2(nx)1    0cos2(nx)nn1nn.0 \leq \cos^2(nx) \leq 1 \implies 0 \leq \frac{\cos^2(nx)}{n \sqrt{n}} \leq \frac{1}{n \sqrt{n}}.

Step 3: Applying the Comparison Test

We compare the series cos2(nx)nn\sum \frac{\cos^2(nx)}{n \sqrt{n}} with the series 1nn\sum \frac{1}{n \sqrt{n}}.

  1. Consider the series:

    n=11nn=n=11n3/2.\sum_{n=1}^{\infty} \frac{1}{n \sqrt{n}} = \sum_{n=1}^{\infty} \frac{1}{n^{3/2}}.

  2. This is a p-series with p=32>1p = \frac{3}{2} > 1, which converges.

Since cos2(nx)nn1nn\frac{\cos^2(nx)}{n \sqrt{n}} \leq \frac{1}{n \sqrt{n}} and 1n3/2\sum \frac{1}{n^{3/2}} converges, by the Comparison Test, the series cos2(nx)nn\sum \frac{\cos^2(nx)}{n \sqrt{n}} also converges.

Step 4: Applying the Alternating Series Test

To confirm the convergence of the original series, we use the Alternating Series Test, which requires:

  1. Decreasing Magnitude: Check if cos2(nx)nn\frac{\cos^2(nx)}{n \sqrt{n}} is decreasing.

    Since cos2(nx)\cos^2(nx) is bounded and the term 1nn\frac{1}{n \sqrt{n}} decreases as nn increases, the product decreases overall.

  2. Limit to Zero: Check if limncos2(nx)nn=0\lim_{n \to \infty} \frac{\cos^2(nx)}{n \sqrt{n}} = 0.

    This limit is zero since 1nn0\frac{1}{n \sqrt{n}} \to 0 as nn \to \infty.

Since both conditions are met, the series converges by the Alternating Series Test.

Conclusion

The series

n=1(1)n1cos2(nx)nn\sum_{n=1}^{\infty} \frac{(-1)^{n-1} \cos^2(nx)}{n \sqrt{n}}

converges.

Would you like further details or have any questions?

Related Questions

  1. How does the Alternating Series Test work in general?
  2. What is the p-series test, and how is it used?
  3. Can a series converge conditionally but not absolutely?
  4. What are some examples of other convergence tests?
  5. How does the behavior of cos(nx)\cos(nx) affect the convergence of series?

Tip: When proving series convergence, always consider testing both absolute and conditional convergence for a complete analysis.

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Math Problem Analysis

Mathematical Concepts

Series Convergence
Alternating Series
Absolute Convergence
Comparison Test

Formulas

General term of the series: (-1)^{n-1} * cos^2(nx) / (n * sqrt(n))
p-series: Σ(1/n^p), where p > 1 converges

Theorems

Alternating Series Test
Comparison Test
p-series Test

Suitable Grade Level

Undergraduate (Calculus Level)