Math Problem Statement
on the graph x/(floor(x)+1) is the derivative continuous
Solution
To determine if the derivative of the function is continuous, let's analyze it step by step:
1. The Function
The function :
- is the greatest integer less than or equal to .
- The value of changes discontinuously at integer values of .
Because is piecewise constant, is piecewise defined over intervals of the form for integer . Within each interval:
2. Differentiability of
Within each interval , is constant. The derivative is: Thus, is differentiable within each interval .
At the boundaries (, where is an integer), the function can have a discontinuity in its derivative because jumps.
3. Continuity of the Derivative
At (integer points):
- As approaches from the left (), the derivative is .
- As approaches from the right (), the derivative is .
These two values of the derivative do not match at , meaning the derivative is discontinuous at integer values of .
Conclusion
The derivative of is not continuous. The points of discontinuity occur at all integers .
Would you like a graph of and its derivative for better visualization?
Expanding Thoughts
Here are 5 related questions:
- What happens to the continuity of itself at integer points?
- How does the choice of denominator () affect the behavior of ?
- Can the derivative of a piecewise-defined function ever be continuous across the boundaries?
- What would happen if the denominator was instead of ?
- How does the floor function affect differentiability compared to the ceiling function?
Tip
When analyzing derivatives of functions involving the floor or ceiling function, always check the behavior at the discontinuities of the floor/ceiling function explicitly!
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Math Problem Analysis
Mathematical Concepts
Calculus
Piecewise Functions
Floor Function
Differentiability
Formulas
f(x) = x / (floor(x) + 1)
f'(x) = 1 / (n + 1) within intervals [n, n+1)
Theorems
Definition of Differentiability
Continuity of Derivatives
Suitable Grade Level
Undergraduate - First Year Calculus
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