Math Problem Statement

on the graph x/(floor(x)+1) is the derivative continuous

Solution

To determine if the derivative of the function f(x)=xx+1f(x) = \frac{x}{\lfloor x \rfloor + 1} is continuous, let's analyze it step by step:

1. The Function f(x)f(x)

The function f(x)=xx+1f(x) = \frac{x}{\lfloor x \rfloor + 1}:

  • x\lfloor x \rfloor is the greatest integer less than or equal to xx.
  • The value of x\lfloor x \rfloor changes discontinuously at integer values of xx.

Because x\lfloor x \rfloor is piecewise constant, f(x)f(x) is piecewise defined over intervals of the form [n,n+1)[n, n+1) for integer nn. Within each interval: f(x)=xn+1, where n=x.f(x) = \frac{x}{n+1}, \text{ where } n = \lfloor x \rfloor.

2. Differentiability of f(x)f(x)

Within each interval [n,n+1)[n, n+1), x\lfloor x \rfloor is constant. The derivative is: f(x)=ddx(xn+1)=1n+1.f'(x) = \frac{d}{dx} \left( \frac{x}{n+1} \right) = \frac{1}{n+1}. Thus, f(x)f(x) is differentiable within each interval [n,n+1)[n, n+1).

At the boundaries (x=nx = n, where nn is an integer), the function f(x)f(x) can have a discontinuity in its derivative because x\lfloor x \rfloor jumps.

3. Continuity of the Derivative

At x=nx = n (integer points):

  • As xx approaches nn from the left (xnx \to n^-), the derivative is 1n+1\frac{1}{n+1}.
  • As xx approaches nn from the right (xn+x \to n^+), the derivative is 1n+2\frac{1}{n+2}.

These two values of the derivative do not match at x=nx = n, meaning the derivative is discontinuous at integer values of xx.

Conclusion

The derivative of f(x)=xx+1f(x) = \frac{x}{\lfloor x \rfloor + 1} is not continuous. The points of discontinuity occur at all integers xx.

Would you like a graph of f(x)f(x) and its derivative for better visualization?


Expanding Thoughts

Here are 5 related questions:

  1. What happens to the continuity of f(x)f(x) itself at integer points?
  2. How does the choice of denominator (x+1\lfloor x \rfloor + 1) affect the behavior of f(x)f(x)?
  3. Can the derivative of a piecewise-defined function ever be continuous across the boundaries?
  4. What would happen if the denominator was x1\lfloor x \rfloor - 1 instead of x+1\lfloor x \rfloor + 1?
  5. How does the floor function affect differentiability compared to the ceiling function?

Tip

When analyzing derivatives of functions involving the floor or ceiling function, always check the behavior at the discontinuities of the floor/ceiling function explicitly!

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Math Problem Analysis

Mathematical Concepts

Calculus
Piecewise Functions
Floor Function
Differentiability

Formulas

f(x) = x / (floor(x) + 1)
f'(x) = 1 / (n + 1) within intervals [n, n+1)

Theorems

Definition of Differentiability
Continuity of Derivatives

Suitable Grade Level

Undergraduate - First Year Calculus