Math Problem Statement
Using a ruler and a pair of compasses only, construct
- Construct a triangle ABC with AB = 7 cm, AC = 8 cm, and triangle ABC = 105 degrees.
- X, the locus of points 6cm from C
- Y, the locus of points equidistant from line AB and line BC to cut X at P and R.
- measure BC
- measure PR
Solution
To construct the required geometrical figures and measurements, follow these steps carefully:
Step 1: Construct Triangle ABC
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Draw Line Segment AB = 7 cm:
- Using a ruler, draw a straight line segment AB with a length of 7 cm.
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Construct Angle 105° at Point A:
- Place the compass on point A, draw an arc across the line AB.
- Keep the same compass width, place the compass point on where the arc cuts AB, and make another arc that cuts the first arc.
- From the intersection of the arcs, draw an arc across AB using the compass.
- Without changing the compass width, move the compass to where the second arc cuts the first arc, and draw another arc to intersect the previous one.
- Using a ruler, draw a line from point A through the intersection of the arcs to create a 105° angle.
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Draw Line Segment AC = 8 cm:
- Place the compass point on point A, and set the compass to 8 cm (AC's length).
- Draw an arc to intersect the line at 105° from AB at a point which we'll call C.
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Draw Line Segment BC:
- Finally, connect point B to point C with a straight line to complete triangle ABC.
Step 2: Construct X, the Locus of Points 6 cm from C
- Draw a Circle with Radius 6 cm Centered at C:
- Place the compass point on point C and set the compass to 6 cm.
- Draw a full circle around point C. This circle represents the locus of points 6 cm away from point C.
Step 3: Construct Y, the Locus of Points Equidistant from Line AB and Line BC
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Construct the Angle Bisector of ∠ABC:
- To find the locus of points equidistant from AB and BC, you need to bisect angle ABC.
- Place the compass on point B, draw arcs across both AB and BC.
- Without changing the compass width, draw two arcs from the points where the first arcs intersected AB and BC.
- The point where these arcs intersect is a point on the angle bisector. Draw the angle bisector from point B through this intersection point.
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Extend the Angle Bisector:
- Extend the angle bisector until it intersects with the circle (locus X) at two points, which we'll call P and R.
Step 4: Measure Line Segment BC
- Measure BC:
- Use a ruler to measure the length of the line segment BC.
Step 5: Measure Line Segment PR
- Measure PR:
- Use a ruler to measure the length of the line segment PR, which is the distance between points P and R.
Results:
- Length of BC: (Use the ruler to measure this and note down the value.)
- Length of PR: (Use the ruler to measure this and note down the value.)
Would you like more details on any of these steps or have any questions?
Follow-up Questions:
- How can you verify that the angle you constructed is exactly 105°?
- What are the possible sources of error in the construction, and how can they be minimized?
- How would you construct a perpendicular bisector of a line segment?
- Can you explain why the locus of points equidistant from two lines is the angle bisector?
- What would happen if the angle between AB and BC was 90°? How would that change the construction?
- How would you construct the locus of points that are 4 cm away from a given point instead of 6 cm?
- How does the construction change if triangle ABC is obtuse or acute?
- What is the significance of the points P and R in geometric constructions?
Tip: Always double-check your compass width and angles during construction to ensure accuracy.
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Math Problem Analysis
Mathematical Concepts
Geometry
Compass and Straightedge Constructions
Angle Bisector
Formulas
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Theorems
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Suitable Grade Level
High School
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