Math Problem Statement

Construct a rhombus pqrs with each side of length 4.5 cm and one diagonal of length 6 CM show this in diagrams

Solution

To construct a rhombus PQRSPQRS with each side measuring 4.5cm4.5 \, \text{cm} and one diagonal measuring 6cm6 \, \text{cm}, you can follow these steps:

Step-by-step Construction

  1. Draw Diagonal PR:

    • Draw a line segment PRPR of length 6cm6 \, \text{cm}. This will be one of the diagonals of the rhombus.
  2. Find the Perpendicular Bisector of PR:

    • Since the diagonals of a rhombus bisect each other at right angles, find the midpoint OO of PRPR.
    • Draw a perpendicular bisector of PRPR through the midpoint OO.
  3. Determine Length of Diagonal SQ:

    • Let the other diagonal be SQSQ, and since it bisects PRPR, it creates two right triangles POSPOS and QORQOR.
    • Using the Pythagorean theorem in one of the right triangles, we have: (SQ2)2+32=4.52\left(\frac{SQ}{2}\right)^2 + 3^2 = 4.5^2 Solving for SQSQ, we get: (SQ2)2=4.5232\left(\frac{SQ}{2}\right)^2 = 4.5^2 - 3^2 SQ2=4.5232\frac{SQ}{2} = \sqrt{4.5^2 - 3^2} SQ=2×4.52325.66cmSQ = 2 \times \sqrt{4.5^2 - 3^2} \approx 5.66 \, \text{cm}
  4. Draw Diagonal SQ:

    • Measure SQ5.66cmSQ \approx 5.66 \, \text{cm} and mark points SS and QQ on the perpendicular bisector such that OO is the midpoint of SQSQ.
  5. Complete the Rhombus:

    • Connect SS to PP and RR, and QQ to PP and RR to form the rhombus PQRSPQRS.

Diagram

Here is the diagram illustrating the construction:

plaintext
S / \ / \ / \ P-------R \ / \ / \ / Q

In this diagram:

  • PR=6cmPR = 6 \, \text{cm} is the given diagonal.
  • PQ=QR=RS=SP=4.5cmPQ = QR = RS = SP = 4.5 \, \text{cm} are the sides of the rhombus.
  • SQ5.66cmSQ \approx 5.66 \, \text{cm} is the other diagonal.

This method uses the property that the diagonals of a rhombus bisect each other at right angles and divides each diagonal into equal halves.

If you have any questions or would like more details on any part of the process, feel free to ask!


Further Exploration

  1. What are the properties of the diagonals of a rhombus?
  2. How can the area of a rhombus be calculated using its diagonals?
  3. Can you construct the rhombus using only a compass and straightedge?
  4. How do the angles in a rhombus relate to its diagonals?
  5. What happens to the shape of a rhombus if one diagonal is longer than the sum of its sides?
  6. Can you identify the type of quadrilateral formed if one diagonal is zero?
  7. How does a rhombus differ from a square, and under what conditions does a rhombus become a square?
  8. Can a rhombus have all angles equal to each other? If so, what special type of rhombus is this?

Tip: When constructing geometrical figures, understanding the properties of the shape can simplify the process and ensure accuracy.

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Math Problem Analysis

Mathematical Concepts

Geometry
Rhombus Construction

Formulas

Pythagorean theorem

Theorems

Properties of Rhombus Diagonals

Suitable Grade Level

High School