Math Problem Statement
Create a four digit number. This number should have:
a 6 with a value that is 10 times greater than the value of 6 in 653 a 3 with a value that is 10 times greater than the value of 3 in 653 a 2 in all the other digit places
Solution
To create a four-digit number based on your criteria:
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The digit 6 must have a value that is 10 times greater than in 653. In 653, the 6 is in the hundreds place (value = 600). Therefore, the 6 must be in the thousands place (value = 6000).
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The digit 3 must have a value that is 10 times greater than in 653. In 653, the 3 is in the tens place (value = 50). Therefore, the 3 must be in the hundreds place (value = 300).
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The remaining digit places should contain 2.
Putting this all together, we have:
- Thousands place: 6
- Hundreds place: 3
- Tens place: 2
- Units place: 2
Thus, the four-digit number is 6322.
If you have any questions or need further details, let me know! Here are some related questions for you:
- How do place values affect the value of digits in a number?
- What other combinations can you create using similar rules?
- Can you explain the importance of zero in place value?
- How would the number change if we replaced the 2s with another digit?
- What is the largest four-digit number you can create under similar rules?
Tip: Understanding place value is essential for manipulating numbers effectively!
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Math Problem Analysis
Mathematical Concepts
Place Value
Multiplication of Place Value
Formulas
Place value rule: The value of a digit is determined by its position in a number and can be scaled by powers of ten.
Theorems
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Suitable Grade Level
Grades 4-6