Create a four digit number. This number should have:

a 6 with a value that is 10 times greater than the value of 6 in 653
a 3 with a value that is 10 times greater than the value of 3 in 653
a 2 in all the other digit places

To create a four-digit number based on your criteria:

1. The digit **6** must have a value that is 10 times greater than in **653**. In **653**, the **6** is in the hundreds place (value = 600). Therefore, the **6** must be in the thousands place (value = 6000).

2. The digit **3** must have a value that is 10 times greater than in **653**. In **653**, the **3** is in the tens place (value = 50). Therefore, the **3** must be in the hundreds place (value = 300).

3. The remaining digit places should contain **2**.

Putting this all together, we have:
- Thousands place: 6
- Hundreds place: 3
- Tens place: 2
- Units place: 2

Thus, the four-digit number is **6322**.

If you have any questions or need further details, let me know! Here are some related questions for you:

1. How do place values affect the value of digits in a number?
2. What other combinations can you create using similar rules?
3. Can you explain the importance of zero in place value?
4. How would the number change if we replaced the 2s with another digit?
5. What is the largest four-digit number you can create under similar rules? 

**Tip:** Understanding place value is essential for manipulating numbers effectively!

Create a four digit number. This number should have: a 6 with a value that is 10 times greater than the value of 6 in 653; a 3 with a value that is 10 times greater than the value of 3 in 653; a 2 in all the other digit places.

Learn how to create a four-digit number where a digit '6' has a value 10 times greater than its value in 653, and a '3' is 10 times greater. The remaining digits are filled with '2'. This problem covers concepts of place value and multiplication by powers of ten, suitable for students in Grades 4-6.

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