Math Problem Statement
Determine a continuous function f(x)f(x) and a real number aa such that:
f(x)f(x) has a critical point at x=ax=a.
f′(x)f′(x) is not defined at x=ax=a.
Both the left-hand limit and the right-hand limit of f′(x)f′(x) as x→ax→a exist and are finite.
The function f(x)f(x) has a point of inflection at x=ax=a.
Find such a function f(x)f(x) and specify the value of aa, providing a detailed explanation of your construction.
Solution
Problem Breakdown and Solution:
To satisfy the given conditions, we must construct a function such that:
-
has a critical point at :
- This implies at .
- Thus, either or at .
-
is not defined at :
- This requires to have a point where does not exist at .
-
The left-hand and right-hand limits of as are finite:
- This suggests a jump discontinuity in the derivative of at .
-
has a point of inflection at :
- This implies changes sign at .
Function Construction:
We propose the piecewise function:
x, & x \leq 0, \\ x^2, & x > 0. \end{cases}$$ #### Verify Properties: 1. **Critical Point at $$x = a = 0$$:** - At $$x = 0$$, $$f(x) = 0$$, so $$f(x)f'(x) = 0$$. - This satisfies the critical point condition. 2. **$$f'(x)$$ not defined at $$x = 0$$:** - For $$x \leq 0$$, $$f'(x) = 1$$. - For $$x > 0$$, $$f'(x) = 2x$$. - Thus, $$f'(x)$$ is not defined at $$x = 0$$ due to a jump discontinuity. 3. **Left-hand and right-hand limits of $$f'(x)$$ as $$x \to 0$$:** - $$\lim_{x \to 0^-} f'(x) = 1$$. - $$\lim_{x \to 0^+} f'(x) = 0$$. - Both limits exist and are finite. 4. **Point of inflection at $$x = 0$$:** - For $$f(x)f(x) = f(x)^2$$: - $$\frac{d}{dx}[f(x)^2] = 2f(x)f'(x)$$. - For $$x < 0$$, $$f(x)^2 = x^2$$ (convex). - For $$x > 0$$, $$f(x)^2 = x^4$$ (concave for small $$x$$). - There is a change in concavity at $$x = 0$$, verifying the point of inflection. --- ### Final Answer: The function is: $$f(x) = \begin{cases} x, & x \leq 0, \\ x^2, & x > 0. \end{cases}$$ The value of $$a$$ is $$0$$. --- Would you like further clarifications? Here are some related questions to explore: 1. How can the concept of left and right derivatives be used in other contexts? 2. Can you derive an alternative piecewise function that satisfies similar conditions? 3. How does the second derivative test apply to points of inflection? 4. What is the geometric significance of jump discontinuities in derivatives? 5. How does this function relate to cusp-like behavior in calculus? **Tip:** When constructing piecewise functions, ensure continuity and evaluate all conditions for differentiability carefully.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Critical points in calculus
Piecewise functions
Continuity and differentiability
Points of inflection
Jump discontinuities in derivatives
Formulas
Critical point condition: f'(x) = 0 or f'(x) is undefined
Inflection point condition: f''(x) changes sign
Theorems
Definition of critical points
Conditions for points of inflection
Piecewise function differentiability rules
Suitable Grade Level
Grades 11-12, College Level
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