To express $A$ and $B$ as consecutive integers around $n$, we can assign expressions based on the nature of consecutive integers.

Since $n$ is in the middle, the numbers around it should be:

• One integer less than $n$, which we will represent as $A = n - 1$.
• One integer more than $n$, which we will represent as $B = n + 1$.

Thus, the expressions for $A$ and $B$ are:

• $A = n - 1$
• $B = n + 1$

This setup creates three consecutive integers: $n - 1$, $n$, and $n + 1$.

Would you like more details or have any further questions?

Here are some related questions to deepen understanding:

1. How would the expressions change if we needed four consecutive integers?
2. What if we needed the sequence to decrease instead of increase?
3. Can you find the sum of these three consecutive integers in terms of $n$?
4. How does this concept apply if $n$ is an even number specifically?
5. How would you express three consecutive odd or even numbers?

Tip: Consecutive integer sequences can always be represented by starting with an integer $n$ and adjusting by increments of 1 (or 2 for consecutive odds/evens).