Math Problem Statement
In a survey funded by the UW school of medicine, 750 of 1,000 adult Seattle residents said they did not believe they could contract a sexually transmitted infection (STI) and 893 of 1,123 Denver residents said they did not believe they could contract an (STI). Construct a 95% confidence interval of the difference in proportions of Seattle and Denver residents who do not believe they could contract a STI. (Use a score of 1.96 for your computations.) (.0809, .0095) (-.0809, -.0095) (-.0809, .0095) (-.0095, .0809)
Solution
To construct a 95% confidence interval for the difference in proportions of Seattle and Denver residents who do not believe they could contract an STI, we will follow these steps:
-
Define the Proportions:
- Let be the proportion of Seattle residents who do not believe they can contract an STI:
- Let be the proportion of Denver residents who do not believe they can contract an STI:
-
Calculate the Difference in Proportions:
-
Calculate the Standard Error (SE) of the Difference: Where:
- (Seattle residents)
- (Denver residents)
Substituting the values:
-
Calculate the Margin of Error (ME):
-
Construct the Confidence Interval:
Thus, rounding to four decimal places, the 95% confidence interval for the difference in proportions is approximately:
(-0.0809, -0.0095)
Conclusion:
The correct answer is (-0.0809, -0.0095).
Would you like more details on any part of this calculation, or do you have any questions? Here are some related questions you might consider:
- How can we interpret the confidence interval in practical terms?
- What assumptions are made when constructing this confidence interval?
- How would the interval change with a different confidence level, like 90%?
- What are the implications of these results for public health messaging?
- How do sample sizes affect the width of a confidence interval?
Tip: Always ensure your sample sizes are adequate to achieve a reliable confidence interval; larger samples generally provide more accurate estimates.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Statistics
Proportions
Confidence Intervals
Formulas
p1 = x1/n1, p2 = x2/n2
Difference in Proportions = p1 - p2
Standard Error (SE) = sqrt[(p1(1 - p1)/n1) + (p2(1 - p2)/n2)]
Margin of Error (ME) = z * SE
Confidence Interval = (Difference in Proportions) ± ME
Theorems
Central Limit Theorem
Proportions Difference Theorem
Suitable Grade Level
Grades 11-12
Related Recommendation
Constructing a 95% Confidence Interval for Proportions in a Survey
Constructing a 95% Confidence Interval for Proportion of Seattle Residents on STI Belief
95% Confidence Interval for the Difference Between Two Proportions (Defective Bolts)
99% Confidence Interval for Difference in Tuna Purchase Proportions
Constructing a 99% Confidence Interval for Reading Proficiency in Colorado