Math Problem Statement
A food safety guideline is that the mercury in fish should be below 1 part per million (ppm). Listed below are the amounts of mercury (ppm) found in tuna sushi sampled at different stores in a major city. Construct a
9999%
confidence interval estimate of the mean amount of mercury in the population.
0.540.54
0.780.78
0.110.11
0.970.97
1.271.27
0.550.55
0.860.86
Question content area bottom
Part 1
What is the confidence interval estimate of the population mean
muμ?
enter your response here
ppmless than<muμless than<enter your response here
ppm
(Round to three decimal places as needed.)
Solution
To construct a 99.99% confidence interval for the population mean of mercury in tuna sushi, we need to follow these steps:
Step 1: Calculate the sample mean
The sample mean is given by:
Where:
- is each sample value
- is the number of samples
The sample values are:
Step 2: Calculate the sample standard deviation
The sample standard deviation is calculated by:
Step 3: Identify the critical t-value
Since the sample size is small (), we will use the t-distribution with degrees of freedom . For a 99.99% confidence interval, the critical value corresponds to the desired confidence level with 6 degrees of freedom.
Step 4: Calculate the margin of error (ME)
The margin of error is given by:
Step 5: Calculate the confidence interval
The confidence interval is:
Let me calculate all the values.The sample mean is approximately 0.726 ppm, and the sample standard deviation is 0.370 ppm.
With a 99.99% confidence level, the confidence interval for the population mean mercury content is:
Thus, the 99.99% confidence interval estimate for the population mean mercury content is approximately between ppm and ppm.
This result suggests a very wide interval due to the extremely high confidence level.
Would you like to go over the details or clarify anything?
Here are five related questions for further exploration:
- How does increasing the confidence level affect the width of a confidence interval?
- What are the implications of a negative lower bound in a confidence interval for real-world data?
- What factors influence the choice between using the t-distribution and the z-distribution?
- How does sample size impact the precision of the confidence interval?
- Why is the margin of error larger at higher confidence levels?
Tip: Confidence intervals become wider as the confidence level increases because you are more certain that the interval contains the population mean.
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Math Problem Analysis
Mathematical Concepts
Statistics
Confidence Intervals
t-Distribution
Sample Mean
Standard Deviation
Formulas
Sample mean: \(\bar{x} = \frac{\sum x_i}{n}\)
Sample standard deviation: \(s = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n-1}}\)
Margin of Error: \(\text{ME} = t_{\alpha/2} \times \frac{s}{\sqrt{n}}\)
Confidence Interval: \(\bar{x} - \text{ME} < \mu < \bar{x} + \text{ME}\)
Theorems
Central Limit Theorem
Student's t-Distribution
Suitable Grade Level
Grades 11-12 and Undergraduate