Math Problem Statement

Question content area top Part 1 A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before​ treatment, 1818 subjects had a mean wake time of 103.0103.0 min. After​ treatment, the 1818 subjects had a mean wake time of 81.381.3 min and a standard deviation of 21.621.6 min. Assume that the 1818 sample values appear to be from a normally distributed population and construct a 9595​% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 103.0103.0 min before the​ treatment? Does the drug appear to be​ effective? Question content area bottom Part 1 Construct the 9595​% confidence interval estimate of the mean wake time for a population with the treatment. enter your response here minless than<muμless than<enter your response here min ​(Round to one decimal place as​ needed.)

Solution

We are asked to construct a 95% confidence interval for the mean wake time after the treatment and assess whether the drug treatment appears effective in reducing wake time.

Step 1: Given information

  • Sample size n=18n = 18
  • Sample mean after treatment xˉ=81.3\bar{x} = 81.3 minutes
  • Sample standard deviation s=21.6s = 21.6 minutes
  • Confidence level 95%95\%

Step 2: Calculate the margin of error (E)

The formula for the margin of error for a confidence interval of the mean is:

E=tα/2×snE = t_{\alpha/2} \times \frac{s}{\sqrt{n}}

where:

  • tα/2t_{\alpha/2} is the critical value of the t-distribution for α=0.05\alpha = 0.05 (for a 95% confidence level) with df=n1=181=17df = n - 1 = 18 - 1 = 17.
  • ss is the sample standard deviation.
  • nn is the sample size.

Using a t-table or calculator, the critical value t0.025,17t_{0.025, 17} for a 95% confidence level with 17 degrees of freedom is approximately 2.110.

Now, calculate the margin of error:

E=2.110×21.618=2.110×21.64.242610.75E = 2.110 \times \frac{21.6}{\sqrt{18}} = 2.110 \times \frac{21.6}{4.2426} \approx 10.75

Step 3: Confidence interval

The confidence interval is given by:

xˉE<μ<xˉ+E\bar{x} - E < \mu < \bar{x} + E

Substituting the values:

81.310.75<μ<81.3+10.7581.3 - 10.75 < \mu < 81.3 + 10.75

70.5<μ<92.170.5 < \mu < 92.1

Step 4: Interpretation

The 95% confidence interval for the mean wake time after treatment is between 70.5 minutes and 92.1 minutes.

Step 5: Effectiveness of the drug

The mean wake time before the treatment was 103.0 minutes. Since the entire confidence interval (70.5 min to 92.1 min) lies below the pre-treatment mean of 103.0 minutes, we can conclude that the drug treatment does appear to be effective in reducing wake time in older subjects.


Would you like any further details or have any questions? Here are some related questions to deepen your understanding:

  1. How is the t-distribution different from the normal distribution in this context?
  2. Why is the t-distribution used instead of the z-distribution here?
  3. What would the confidence interval look like if we had a larger sample size?
  4. How does the confidence level affect the width of the confidence interval?
  5. Can we conclude causality from this confidence interval analysis alone?

Tip: A larger sample size reduces the margin of error, leading to a narrower confidence interval.

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Math Problem Analysis

Mathematical Concepts

Confidence Intervals
Statistical Inference
Hypothesis Testing

Formulas

E = t_alpha/2 * (s / sqrt(n))
Confidence Interval: x̄ - E < μ < x̄ + E

Theorems

Central Limit Theorem
t-Distribution

Suitable Grade Level

Undergraduate Statistics