Math Problem Statement
Conduct the hypothesis test and provide the test statistic and the critical value, and state the conclusion.
A company claims that its packages of 100 candies are distributed with the following color percentages:
1515%
red,
2121%
orange,
1616%
yellow,
1010%
brown,
2323%
blue, and
1515%
green. Use the given sample data to test the claim that the color distribution is as claimed. Use a
0.100.10
significance level.
Color Number_in_Package
Red 14
Orange 25
Yellow 10
Brown 6
Blue 27
Green 18
The test statistic is
enter your response here.
(Round to two decimal places as needed.)
Part 2
The critical value is
enter your response here.
(Round to three decimal places as needed.)
Part 3
State the conclusion.
▼ Do not reject
Reject
Upper H 0H0.
There
▼ is
is not
sufficient evidence to warrant rejection of the claim that the color distribution is as claimed.
Solution
To test the company's claim about the color distribution of candies, we will perform a chi-square goodness-of-fit test.
Step-by-Step Solution
1. State the hypotheses:
- Null Hypothesis (): The color distribution of the candies is as claimed by the company.
- Alternative Hypothesis (): The color distribution of the candies is not as claimed by the company.
2. Observed Frequencies:
The observed frequencies for each color are given as:
- Red:
- Orange:
- Yellow:
- Brown:
- Blue:
- Green:
3. Expected Frequencies:
The expected frequencies for each color, based on the company's claim, are:
- Red:
- Orange:
- Yellow:
- Brown:
- Blue:
- Green:
4. Calculate the chi-square test statistic:
The chi-square test statistic is calculated using the formula: Where are the observed frequencies and are the expected frequencies.
Calculations:
\chi^2 &= \frac{(14 - 15)^2}{15} + \frac{(25 - 21)^2}{21} + \frac{(10 - 16)^2}{16} + \frac{(6 - 10)^2}{10} + \frac{(27 - 23)^2}{23} + \frac{(18 - 15)^2}{15} \\ &= \frac{1}{15} + \frac{16}{21} + \frac{36}{16} + \frac{16}{10} + \frac{16}{23} + \frac{9}{15} \\ &= 0.067 + 0.762 + 2.250 + 1.600 + 0.696 + 0.600 \\ &= 5.975 \end{align*}$$ The test statistic is $$\chi^2 = 5.975$$. #### 5. Determine the critical value: For a chi-square test with $$k - 1$$ degrees of freedom (where $$k$$ is the number of categories), and a significance level of 0.10, we look up the critical value in the chi-square distribution table. Degrees of freedom ($$df$$) = $$6 - 1 = 5$$ Using the chi-square distribution table, the critical value for $$\alpha = 0.10$$ and $$df = 5$$ is approximately $$\chi^2_{crit} = 9.236$$. #### 6. Compare the test statistic to the critical value and make a conclusion: - If $$\chi^2 > \chi^2_{crit}$$, we reject the null hypothesis. - If $$\chi^2 \leq \chi^2_{crit}$$, we do not reject the null hypothesis. Since $$\chi^2 = 5.975$$ is less than $$\chi^2_{crit} = 9.236$$, we do not reject the null hypothesis. #### Conclusion: There is not sufficient evidence to warrant rejection of the claim that the color distribution is as claimed. ### Summary 1. **Test Statistic**: $$\chi^2 = 5.975$$ (rounded to two decimal places) 2. **Critical Value**: $$\chi^2_{crit} = 9.236$$ (rounded to three decimal places) 3. **Conclusion**: Do not reject $$H_0$$. There is not sufficient evidence to warrant rejection of the claim that the color distribution is as claimed. --- Do you want details or have any questions? Here are some questions you can ask: 1. How do I calculate the chi-square test statistic? 2. What is the significance level in hypothesis testing? 3. How do I interpret the chi-square distribution table? 4. What are the steps to perform a chi-square goodness-of-fit test? 5. Can you explain the degrees of freedom in this context? **Tip**: When conducting a chi-square goodness-of-fit test, ensure that the expected frequencies are not too small. Ideally, they should be at least 5 in each category to apply the chi-square test reliably.Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Hypothesis Testing
Chi-square Test
Goodness-of-Fit Test
Formulas
Chi-square Test Statistic
Theorems
-
Suitable Grade Level
Advanced Undergraduate
Related Recommendation
Chi-Square Goodness-of-Fit Test for Candy Color Distribution
Chi-Square Goodness-of-Fit Test for Candy Distribution
Chi-Square Goodness-of-Fit Test for Candy Color Distribution
Chi-Square Goodness-of-Fit Hypotheses for Candy Color Distribution
Chi-square Goodness-of-Fit Test for Color Preference Distribution