Math Problem Statement
answer
Solution
The problem asks to transform the statement:
"If the integer is even, then is odd."
This is a conditional statement in logic. Let's break down each part of the solution: disjunctive form, negation, contrapositive, inverse, and converse.
Let’s define:
- : "The integer is even."
- : " is odd."
The statement in symbolic form is:
1. Disjunctive form:
The disjunctive form of an implication is logically equivalent to . This is read as "not or ".
- So, for our case: Which translates to: "If is not even, or is odd."
2. Negation:
To negate , we use the fact that the negation of an implication is .
- So, negating the statement: This translates to: "The integer is even, and is not odd."
3. Contrapositive:
The contrapositive of is .
- So, the contrapositive is: "If is not odd, then is not even." Which simplifies to: "If is even, then is odd."
4. Inverse:
The inverse of is .
- So, the inverse is: "If is not even, then is not odd." Which simplifies to: "If is odd, then is even."
5. Converse:
The converse of is .
- So, the converse is: "If is odd, then is even."
Would you like any further clarification or details on these transformations? Here are 5 related questions that may expand your understanding:
- What is the difference between the contrapositive and converse of a statement?
- How do you prove that is logically equivalent to ?
- How do negation rules apply to compound statements like conjunctions and disjunctions?
- Can the inverse and converse of a statement ever both be true?
- How can you construct truth tables for implications, converses, and inverses?
Tip: Always remember that the contrapositive of a statement is logically equivalent to the original statement, but the inverse and converse are not guaranteed to be true.
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Math Problem Analysis
Mathematical Concepts
Logical Implications
Conditional Statements
Negation
Contrapositive
Inverse
Converse
Formulas
Disjunctive form: ¬p ∨ q
Negation: p ∧ ¬q
Contrapositive: ¬q → ¬p
Inverse: ¬p → ¬q
Converse: q → p
Theorems
Logical Equivalence
De Morgan's Laws
Suitable Grade Level
College-level Logic or Advanced High School Math
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